我尝试通过从每个组中选择第一行来删除重复的行。 例如
PK Col1 Col2
1 A B
2 A B
3 C C
4 C C
我想要一个回报:
PK Col1 Col2
1 A B
3 C C
我尝试了以下代码,但它没有工作:
DataTable dt = GetSampleDataTable(); //Get the table above.
dt = dt.Select("SELECT MIN(PK), Col1, Col2 GROUP BY Col1, Col2);
答案 0 :(得分:34)
DataTable
的{{1}}方法仅支持Select
等简单过滤表达式。它不支持复杂的表达式,更不用说SQL / Linq语句了。
但是,您可以使用Linq扩展方法提取{field} = {value}
的集合,然后创建 new DataRow
。
DataTable
答案 1 :(得分:6)
dt = dt.AsEnumerable().GroupBy(r => r.Field<int>("ID")).Select(g => g.First()).CopyToDataTable();
答案 2 :(得分:4)
Tim Schmelter回答https://stackoverflow.com/a/8472044/26877
public DataTable GroupBy(string i_sGroupByColumn, string i_sAggregateColumn, DataTable i_dSourceTable)
{
DataView dv = new DataView(i_dSourceTable);
//getting distinct values for group column
DataTable dtGroup = dv.ToTable(true, new string[] { i_sGroupByColumn });
//adding column for the row count
dtGroup.Columns.Add("Count", typeof(int));
//looping thru distinct values for the group, counting
foreach (DataRow dr in dtGroup.Rows) {
dr["Count"] = i_dSourceTable.Compute("Count(" + i_sAggregateColumn + ")", i_sGroupByColumn + " = '" + dr[i_sGroupByColumn] + "'");
}
//returning grouped/counted result
return dtGroup;
}
示例:
DataTable desiredResult = GroupBy("TeamID", "MemberID", dt);
答案 3 :(得分:1)
dt.AsEnumerable()
.GroupBy(r => new { Col1 = r["Col1"], Col2 = r["Col2"] })
.Select(g =>
{
var row = dt.NewRow();
row["PK"] = g.Min(r => r.Field<int>("PK"));
row["Col1"] = g.Key.Col1;
row["Col2"] = g.Key.Col2;
return row;
})
.CopyToDataTable();
答案 4 :(得分:0)
此解决方案按Col1排序,按Col2排序。然后提取Col2的值并将其显示在mbox中。
var grouped = from DataRow dr in dt.Rows orderby dr["Col1"] group dr by dr["Col2"];
string x = "";
foreach (var k in grouped) x += (string)(k.ElementAt(0)["Col2"]) + Environment.NewLine;
MessageBox.Show(x);