我使用此存储过程来显示待处理的文档
create procedure b
as
select
dbo.DocumentInfo.DocID, dbo.DocumentInfo.DocName,
dbo.DocumentInfo.Uploadfile, dbo.DocType.Doc Type,
dbo.Department.DepType, ApproveType.ApproveType
from
dbo.DocumentInfo
left join
dbo.DocType on dbo.DocumentInfo.DocTypeID = dbo.DocType.DocTypeID
left join
dbo.Department on dbo.DocumentInfo.DepID = dbo.Department.DepID
inner join
ApproveType on DocumentInfo.ApproveID = ApproveType.ApproveID
and (ApproveType.ApproveID = 3)
但是当我查看此查询时,它无法向我显示任何文档..
问题出在哪里?
答案 0 :(得分:0)
您的问题是您在连接排除数据的表上直接加入(INNER JOIN)。因此,表ApproveID
中的列DocumentInfo
不包含任何数据,或者列ApproveType
的表ApproveID
中没有匹配的行。
在我看来,如果你打算以这种方式使用这个存储过程,你在任何情况下使用连接都是错误的 - 你绝对可以考虑使用表别名,如下所示:
CREATE PROCEDURE b
AS
SELECT di.DocID,
di.DocName,
di.Uploadfile,
dt.DocType,
d.DepType,
at.ApproveType
FROM DocumentInfo di
LEFT OUTER JOIN
DocType dt ON dt.DocTypeID = di.DocTypeID
LEFT OUTER JOIN
Department d ON d.DepID = di.DepID
LEFT OUTER JOIN
ApproveType at ON at.ApproveID = di.ApproveID
AND at.ApproveID = 3