首先,我是D3的新手。 我试图在单个D3图中实现不同的行为,使用以下示例:
但我的图表在几秒钟后冻结,我不明白为什么......
这是我的代码:http://jsfiddle.net/blt909/aVhd8/20/ [工作精细版本]
var margin = {top: -5, right: -5, bottom: -5, left: -5};
var width = 500 - margin.left - margin.right,
height = 400- margin.top - margin.bottom;
var color = d3.scale.category20();
var force = d3.layout.force()
.charge(-200)
.linkDistance(50)
.size([width + margin.left + margin.right, height + margin.top + margin.bottom]);
var zoom = d3.behavior.zoom()
.scaleExtent([1, 10])
.on("zoom", zoomed);
var drag = d3.behavior.drag()
.origin(function(d) { return d; })
.on("dragstart", dragstarted)
.on("drag", dragged)
.on("dragend", dragended);
var svg = d3.select("#map").append("svg")
.attr("width", width + margin.left + margin.right)
.attr("height", height + margin.top + margin.bottom)
.append("g")
.attr("transform", "translate(" + margin.left + "," + margin.right + ")")
.call(zoom);
var rect = svg.append("rect")
.attr("width", width)
.attr("height", height)
.style("fill", "none")
.style("pointer-events", "all");
var container = svg.append("g");
force
.nodes(graph.nodes)
.links(graph.links)
.start();
var tooltip = d3.select("body")
.append("foreignObject")
.append("xhtml:div")
.attr("id", "tooltip")
.style("position", "absolute")
.style("z-index", "10")
.style("color", "#eeeeee")
.style("visibility", "hidden")
.text("");
var link = container.append("g")
.attr("class", "links")
.selectAll(".link")
.data(graph.links)
.enter().append("line")
.attr("class", "link")
.style("stroke-width", function(d) { return Math.sqrt(d.value); });
var node = container.append("g")
.attr("class", "nodes")
.selectAll(".node")
.data(graph.nodes)
.enter().append("g")
.attr("class", "node")
.attr("cx", function(d) { return d.x; })
.attr("cy", function(d) { return d.y; })
.call(drag);
node.append("circle")
.attr("r", function(d) { return d.weight * 2+ 12; })
.style("fill", function(d) { return color(1/d.rating); });
force.on("tick", function() {
link.attr("x1", function(d) { return d.source.x; })
.attr("y1", function(d) { return d.source.y; })
.attr("x2", function(d) { return d.target.x; })
.attr("y2", function(d) { return d.target.y; });
node.attr("transform", function(d) { return "translate(" + d.x + "," + d.y + ")"; });
});
var linkedByIndex = {};
graph.links.forEach(function(d) {
linkedByIndex[d.source.index + "," + d.target.index] = 1;
});
function isConnected(a, b) {
return linkedByIndex[a.index + "," + b.index] || linkedByIndex[b.index + "," + a.index];
}
node.on("mouseover", function(d){
node.classed("node-active", function(o) {
thisOpacity = isConnected(d, o) ? true : false;
this.setAttribute('fill-opacity', thisOpacity);
return thisOpacity;
});
link.classed("link-active", function(o) {
return o.source === d || o.target === d ? true : false;
});
d3.select(this).classed("node-active", true);
d3.select(this).select("circle").transition()
.duration(750)
.attr("r", (d.weight * 2+ 12)*1.5);
})
.on("mouseout", function(d){
node.classed("node-active", false);
link.classed("link-active", false);
d3.select(this).select("circle").transition()
.duration(750)
.attr("r", d.weight * 2+ 12);
});
function dottype(d) {
d.x = +d.x;
d.y = +d.y;
return d;
}
function zoomed() {
container.attr("transform", "translate(" + d3.event.translate + ")scale(" + d3.event.scale + ")");
}
function dragstarted(d) {
d3.event.sourceEvent.stopPropagation();
d3.select(this).classed("dragging", true);
//ADDING force.start(); HERE SOLVES THE ISSUE
force.start();
}
function dragged(d) {
d3.select(this).attr("cx", d.x = d3.event.x).attr("cy", d.y = d3.event.y);
}
function dragended(d) {
d3.select(this).classed("dragging", false);
}
感谢您的帮助
答案 0 :(得分:3)
使用force.start();里面的dragstarted函数停止冻结。
function dragstarted(d) {
d3.event.sourceEvent.stopPropagation();
d3.select(this).classed("dragging", true);
force.start();
};
这是fiddle