我试图让结果表包含行
Condition1: A.pc=B.pc AND
Condition2: (preferred (A.sub = B.Sub) or
else any one row that satisfy only Condition1)
我尝试过以下内连接查询和其他一些连接和子查询,但无法弄清楚编写具有上述奇怪条件的查询的确切方法。
SELECT * FROM tblA AS A INNER JOIN tblB AS B
ON A.sub=B.sub
WHERE A.pc=B.pc
tblA
-------------------
| id | pc | sub |
-------------------
| 0 | 5 | abc |
| 1 | 8 | def |
| 2 | 6 | ghi |
| 3 | 2 | jkl |
| 4 | 7 | mno |
| 5 | 19 | pqr |
-------------------
tblB
-------------------------
| pc | sub | uml | ull |
-------------------------
| 3 |arm | 1 | 1 |
| 3 |gtk | 1 | 2 |
| 3 |lmn | 1 | 3 |
| 3 |pop | 1 | 4 |
| 5 |abc | 1 | 5 |
| 5 |hlq | 1 | 6 |
| 5 |pon | 2 | 1 |
| 5 |qrt | 2 | 2 |
| 7 |alo | 2 | 3 |
| 7 |mno | 2 | 4 |
| 7 |ghm | 2 | 5 |
| 7 |stm | 2 | 6 |
| 9 |mck | 2 | 7 |
| 9 |plo | 3 | 1 |
| 9 |rtk | 3 | 2 |
| 9 |ert | 3 | 3 |
| 6 |gji | 3 | 4 |
| 6 |ghi | 3 | 5 |
| 6 |yux | 4 | 1 |
| 6 |del | 4 | 2 |
| 2 |jkl | 4 | 3 |
| 2 |jll | 5 | 4 |
| 2 |uin | 6 | 1 |
| 2 |tro | 6 | 2 |
| 19 |ppm | 6 | 3 |
| 19 |kde | 6 | 4 |
| 19 |grp | 6 | 5 |
| 19 |sho | 6 | 6 |
-------------------------
Expected Result Table:
-------------------------------
| id | pc | sub | uml | ull |
-------------------------------
| 0 | 5 |abc | 1 | 5 |
| 2 | 6 |ghi | 3 | 5 |
| 3 | 2 |jkl | 4 | 3 |
| 4 | 7 |mno | 2 | 4 |
| 5 | 19 |ppm | 6 | 3 | *
-------------------------------
* notice this is a arbitrary row as (A.sub=B.sub) not found
** notice there is no result for id=1 as pc=8 do not exist in tblB
答案 0 :(得分:1)
在有人提出更好的答案之前,这里有一些代码能够满足您的需求 请注意,就性能而言,这可能不是一个好的解决方案(特别是随着您的桌面增长)。
SELECT *
FROM (
SELECT tblA.id, tblB.*
FROM tblA INNER JOIN tblB
ON tblA.pc = tblB.pc AND
tblA.id NOT IN (SELECT tblA.id
FROM tblA INNER JOIN tblB
ON tblA.sub = tblB.sub)
GROUP BY tblA.id
UNION
SELECT tblA.id, tblB.*
FROM tblA INNER JOIN tblB
ON tblA.sub = tblB.sub
GROUP BY tblA.id
) AS tu
ORDER BY id ASC;
另请参阅此 short demo 。
答案 1 :(得分:0)
我想出的一种方法是在where子句中重复连接条件:
SELECT *
FROM tblA AS A
INNER JOIN tblB AS B
ON A.pc = B.pc
WHERE A.sub = B.sub
OR A.pc = B.pc