Question

table:panel   

id PanelName email_id status
1   A        1        0
2   B        1        1 
3   C        1        0
4   D        1        1 
5   E        1        1 
-------------------------
6   A1       2        0 
7   B1       2        1 
8   C1       2        0
-------------------------
9   D1       3        1 
10  E1       3        1

我需要状态为1（B,D,E）的user1的所有面板以及用户1的面板总数= 5以及用户1的面板的所有计数状态= 0，即单个查询中的2。

select p.*,Count(p1.id) as totalPanels
from panel p
INNER join panel p1 on (p.email_id=p1.email_id)
where p.email_id=1 and p.status =1
Group by p.id

这给了我所有面板的状态1和总面板数。但是如何在同一个查询中统计状态为0的面板？

Expected output will be:

id |PanelName| email_id |status| TotalPanel| Rejectedpanel

1   A          1         0       5           2
2   B          1         1       5           2
3   C          1         0       5           2 
4   D          1         1       5           2
5   E          1         1       5           2

另一个原因是子查询如下，但我不必使用

 select p.id,Count(p1.id) as totalPanels,
(select count(id) from panel p2 where p2.status=0 and p2.email_id=p.email_id ) as RejectePanel 
 from panel p
INNER join panel p1 on (p.email_id=p1.email_id)

where p.email_id=1 
Group by p.id

请建议，谢谢。

Answer 1

好吧，我完全会选择2个不同的查询，但这里是符合您预期输出的混合内容：

SELECT p1.*,
  (SELECT count(*) FROM panel p2
   WHERE p1.email_id = p2.email_id) TotalPanel,
  (SELECT sum(status = 0) FROM panel p2
   WHERE p1.email_id = p2.email_id) RejectedPanel
FROM panel p1
WHERE p1.email_id = 1

小提琴here。

Answer 2

不确定为什么你不能使用子查询，尽管我通常会避免使用核心子查询。

你可以试试这样的事情

SELECT p.*, TotalPanel, AcceptedPanel, RejectedPanel
FROM panel p
INNER JOIN
(
    SELECT email_id, COUNT(*) AS TotalPanel, SUM(IF(status = 1, 1, 0)) AS AcceptedPanel, SUM(IF(status = 0, 1, 0)) AS RejectedPanel
    FROM panel 
    GROUP BY email_id
) Sub1
ON p.email_id = Sub1.email_id
WHERE p.email_id = 1

带来所有记录以及mysql中具有不同状态的记录数

2 个答案: