Question

我有这种TSQL语法：

WITH cte AS(
SELECT Stamps, row_number() over (order by (SELECT 1)) rn from week
unpivot      
(Stamps FOR Day IN ([Sun], [Mon], [Tue], [Wed], [Thu], [Fri], [Sat]) ) AS unpvt )

SELECT Stamps + ': ' +STUFF((SELECT ','+cast(rn as varchar(9)) from cte where Stamps=A.TimeStamps FOR XML PATH('')), 1 , 1 , '' ) from cte A group by Stamps

这给了我每张“邮票”当天的号码。例如，如果表是：

S2 | S0 | S0 | S1 | S1 | S3 | S2

结果将是：

S0 : 2,3
S1 : 4,5
S2 : 1,7
S3 : 6

这部分效果很好，但现在我想把这个结果放在表格中

赞Insert Into mytable (S0, S1, S2, S3) = ('2,3','4,5','1,7','6')

但是当我在它之后或之前设置它不起作用。我该怎么做？感谢

Answer 1

我想你想把它转回来。怎么样：

WITH cte AS(
SELECT Stamps, row_number() over (order by (SELECT 1)) rn from week
unpivot      
(Stamps FOR Day IN ([Sun], [Mon], [Tue], [Wed], [Thu], [Fri], [Sat]) ) AS unpvt 
), cte2 AS (

SELECT Stamps , STUFF((SELECT ','+cast(rn as varchar(9)) 
                             from cte where Stamps=A.[Stamps] FOR XML PATH('')), 1 , 1 , '' ) 
  as DayList
from cte A
group by Stamps
)
INSERT MyTable (S0, S1, S2, S3)
select S0, S1, S2, S3 from cte2
PIVOT
(
Max(DayList)
FOR Stamps IN ([S0], [S1], [S2], [S3])
) AS PivotTable;

SQL小提琴：http://sqlfiddle.com/#!6/37ff8/2

T-SQL：在CTE的表结果中插入

1 个答案: