我试图让函数写入一个文件,其中有4个不同的字符串变量传递到写入的内容中,但无论出于何种原因,我都会这样做:
Traceback (most recent call last):
File "C:\Python Files\writePy\writePy.py", line 34, in <module>
indent = writeIf(mFile, genCond(), lFile, indent)
File "C:\Python Files\writePy\writePy.py", line 23, in writeIf
file.write('%sif (%s %s %s):' (indentation, cond[0], cond[1], cond[2]))
TypeError: 'str' object is not callable
这是我的主要代码:
# Main code
lFile = open('OperationLog.txt', mode='w') # Log file for changes
mFile = open('Evolve.txt', mode='w+') # File to be edited
indent = 0 # Indentation for written code
# Write two IF statements with a randomized condition to file, update indentation
indent = writeIf(mFile, genCond(), lFile, indent)
indent = writeIf(mFile, genCond(), lFile, indent)
# Close files
lFile.close()
mFile.close()
这是错误所在的函数:
def writeIf(file, cond, log, indent):
indentation = ' ' * (4 * indent) # Number of spaces to add is 4 * indent
file.write('%sif (%s %s %s):' (indentation, cond[0], cond[1], cond[2]))
indent = indent + 1
log.write('Added: IF statement to %s.' % file.name)
return indent
答案 0 :(得分:9)
您忘记了模运算符(%
):
file.write('%sif (%s %s %s):' % (indentation, cond[0], cond[1], cond[2]))
# here --^
答案 1 :(得分:5)
在这种情况下使用format()
功能,因为它更适合和易于维护
file.write('{0}if ({1}{2}{3}):'.format(indentation, cond[0], cond[1], cond[2]))
答案 2 :(得分:4)
您必须使用字符串格式:
file.write('%sif (%s %s %s):' % (indentation, cond[0], cond[1], cond[2]))
如果没有模运算符(%),Python会将其解释为函数调用:
file.write('string'(indentation, cond[0], cond[1], cond[2]))
答案 3 :(得分:3)
虽然这些答案肯定能解决您的问题,但您也应该了解logging module。
import logging
log = logging.getLogger(__name__) #or whatever name you want, like 'my_logger'
log.setLevel(logging.DEBUG)
log.addHandler(logging.FileHandler('OperationLog.txt', mode=w')) #default is 'a'ppend mode
然后你的功能看起来像这样:
def writeIf(file, cond, indent):
indentation = ' ' * (4 * indent) # Number of spaces to add is 4 * indent
file.write('%sif (%s %s %s):' % (indentation, cond[0], cond[1], cond[2]))
indent = indent + 1
log.debug('Added: IF statement to %s.', file.name)
return indent