Question

我有一个Oracle数据库，我有一个显示日期范围的表：

23/12/2011  08/01/2012
06/01/2012  06/01/2012
19/03/2012  19/03/2012
05/04/2012  05/04/2012
06/04/2012  06/04/2012
30/04/2012  30/04/2012
01/05/2012  01/05/2012
02/05/2012  02/05/2012
15/08/2012  15/08/2012
12/10/2012  12/10/2012
01/11/2012  01/11/2012
06/12/2012  06/12/2012
07/12/2012  07/12/2012
08/12/2012  08/12/2012
25/12/2012  25/12/2012
09/01/2013  26/01/2013
20/05/2013  08/06/2013
24/06/2013  13/07/2013
18/01/2013  02/02/2013
24/05/2013  08/06/2013

我希望用一个日期跨越这个表，检查日期不在表格的一对日期中，如下所示：

 select * 
from table
where table.date NOT BETWEEN 
(SELECT DT_START FROM CALENDARIO) AND (SELECT DT_END FROM CALENDARIO))

但BETWEEN不接受数组作为条目，那么有没有办法实现这个？

提前致谢！

Answer 1

试试这个希望这对你有所帮助

WHERE (d.date1 NOT BETWEEN '2011-11-09 13:08:46' AND '2011-11-11 16:08:46') 
   OR (d.date2 NOT BETWEEN '2011-11-09 13:08:46' AND '2011-11-11 16:08:46') 
   OR (d.date3 NOT BETWEEN '2011-11-09 13:08:46' AND '2011-11-11 16:08:46')

Answer 2

你可以尝试：

select * 
from table t1
where not exists (
  select null
  from   CALENDARIO
  where  t1.my_date between dt_start and dt_end)

Answer 3

我同意@David Aldrige，要么不存在，要么不存在。

NOT IN和Cross Joining似乎有一个更好的解释计划，如果它是你担心的表现http://sqlfiddle.com/#!4/7159f/6

BETWEEN数组日期

3 个答案: