Question

我是SQL的新手，所以这个问题可能很愚蠢。

以下是相关表格的示例行：学生：

+-------+----------+---------+------+------+-------+---------+-----------+
| StuID | LName    | Fname   | Age  | Sex  | Major | Advisor | city_code |
+-------+----------+---------+------+------+-------+---------+-----------+
|  1001 | Smith    | Linda   |   18 | F    |   600 |    1121 | BAL       |

Minor_in：

+-------+------+
| StuID | DNO  |
+-------+------+
|  1004 |  520 |

百货商店：

+------+----------+--------------------------+------+--------------+--------+
| DNO  | Division | DName                    | Room | Building     | DPhone |
+------+----------+--------------------------+------+--------------+--------+
|   10 | AS       | History of Art           | 268  | Mergenthaler |   7117 |

我想找到CS Major中最受欢迎的学生（DNO = 600）这是我的查询，它有效，但它很难看：

SELECT DNO, count 
FROM (SELECT DNO, COUNT(*) AS count
      FROM Minor_in
      WHERE StuID IN (SELECT StuID
                      FROM Student
                      WHERE (Major = 550 OR Major = 600))
      GROUP BY DNO
) AS C1
WHERE count IN (
                SELECT MAX(count)
                FROM (
                      SELECT DNO, COUNT(*) AS count
                      FROM Minor_in
                      WHERE StuID IN (SELECT StuID
                                      FROM Student
                                      WHERE (Major = 550 OR Major = 600))
                      GROUP BY DNO
                      ) AS MinorCount
                );

还有更好的方法吗？非常感谢！

Answer 1

这个怎么样？

select stuid.dno, count (*)
from stuid inner join student
on stuid.stuid = student.stuid 
where student.major in (550, 600)
group by stuid.dno
order by count (*) desc

我假设dnos 550和600是计算机科学课程

找到CS中最受欢迎的学生

1 个答案: