我想从字符串中找到段落,然后对它们进行格式化,我有什么工作,但它不能100%工作。
所以,我有这个字符串,如下所示:
##Chapter 1
Once upon a time there was a little girl named sally, she went to school.
One day it was awesome!
##Chapter 2
We all had a parade!
我通过将##...
转换为<H2>
来格式化字符串,现在看起来像这样:
<h2>Chapter 1</h2>
Once upon a time there was a little girl named sally, she went to school.
One day it was awesome!
<h2>Chapter 2</h2>
We all had a parade!
现在我想将所有内容转换为段落,为此我这样做:
// Converts sections to paragraphs:
$this->string = preg_replace("/(^|\n\n)(.+?)(\n\n|$)/", "<p>$2</p>", $this->string);
// To Remove paragraph tags from header tags (h1,h2,h3,h4,h5,h6,h7):
$this->string = preg_replace("/<p><h(\d)>(.+?)<\/h\d><\/p>/i", "<h$1>$2</h$1>", $this->string);
这是最终输出(添加新行以提高可读性):
<h2>Chapter 1</h2>
Once upon a time there was a little girl named sally, she went to school.
<p>One day it was awesome!</p>
<h2>Chapter 2</h2>
<p>We all had a parade!</p>
正如我在开头附近所说的那样,这不起作用100%,并且你可以看到第一段没有添加段落。我该怎么做才能改善正则表达式?
答案 0 :(得分:1)
你可以一步完成:
$this->string = preg_replace('~(*BSR_ANYCRLF)\R\R\K(?>[^<\r\n]++|<(?!h[1-6]\b)|\R(?!\R))+(?=\R\R|$)~u',
'<p>$0</p>', $this->string);
模式详情
(*BSR_ANYCRLF) # \R can be any type of newline
\R\R # two newlines
\K # reset the match
(?> # open an atomic group
[^<\r\n]++ # all characters except <, CR, LF
| # OR
<(?!h[1-6]\b) # < not followed by a header tag
| # OR
\R(?!\R) # single newline
)+ # close the atomic group and repeat one or more times
(?=\R\R|$) # followed by to newlines or the end of the string
答案 1 :(得分:0)
将m开关添加到第一个正则表达式。
// Converts sections to paragraphs:
$this->string = preg_replace("/(^|\n\n)(.+?)(\n\n|$)/m", "<p>$2</p>", $this->string);
// To Remove paragraph tags from header tags (h1,h2,h3,h4,h5,h6,h7):
$this->string = preg_replace("/<p><h(\d)>(.+?)<\/h\d><\/p>/i", "<h$1>$2</h$1>", $this->string);