我正在使用谷歌的地理编码API,但它返回XML,我不知道如何解析它。
我正试图在XML文档中获得看起来像这样的自由......
<GeocodeResponse>
<status>OK</status>
<result>
<type>street_address</type>
<formatted_address>1600 Amphitheatre Pkwy, Mountain View, CA 94043, USA</formatted_address>
<address_component>
<long_name>1600</long_name>
<short_name>1600</short_name>
<type>street_number</type>
</address_component>
<address_component>
<long_name>Amphitheatre Pkwy</long_name>
<short_name>Amphitheatre Pkwy</short_name>
<type>route</type>
</address_component>
<address_component>
<long_name>Mountain View</long_name>
<short_name>Mountain View</short_name>
<type>locality</type>
<type>political</type>
</address_component>
<address_component>
<long_name>San Jose</long_name>
<short_name>San Jose</short_name>
<type>administrative_area_level_3</type>
<type>political</type>
</address_component>
<address_component>
<long_name>Santa Clara</long_name>
<short_name>Santa Clara</short_name>
<type>administrative_area_level_2</type>
<type>political</type>
</address_component>
<address_component>
<long_name>California</long_name>
<short_name>CA</short_name>
<type>administrative_area_level_1</type>
<type>political</type>
</address_component>
<address_component>
<long_name>United States</long_name>
<short_name>US</short_name>
<type>country</type>
<type>political</type>
</address_component>
<address_component>
<long_name>94043</long_name>
<short_name>94043</short_name>
<type>postal_code</type>
</address_component>
<geometry>
<location>
<lat>37.4217550</lat>
<lng>-122.0846330</lng>
</location>
<location_type>ROOFTOP</location_type>
<viewport>
<southwest>
<lat>37.4188514</lat>
<lng>-122.0874526</lng>
</southwest>
<northeast>
<lat>37.4251466</lat>
<lng>-122.0811574</lng>
</northeast>
</viewport>
</geometry>
</result>
</GeocodeResponse>
我该怎么做?这是我可以达到的目的。
string baseURL = "https://maps.googleapis.com/maps/api/geocode/xml?";
string fullURL = baseURL + "address=" + address + "&sensor=false";
Uri ServivrUri = new Uri(fullURL);
WebClient proxy = new WebClient();
byte[] abc = proxy.DownloadData(ServivrUri);
MemoryStream stream = new MemoryStream(abc);
XmlDocument xDocument = new XmlDocument();
xDocument.Load(stream);
答案 0 :(得分:2)
您应该使用XDocument
代替XmlDocument
var xDocument = XDocument.Load(stream);
然后你可以使用linqToXml
例如,要获得纬度,您可以试试这个
var latitude = xDocument.Descendants("geometry").Descendants("location")
.First().Element("lat").Value;