Question

我希望将queryvars写出来分隔文件。我已经调查了它，我很确定我需要将它移动到另一个文件并将其导入该文件。我对建议很开放：

def nestForLoop():
    lines = open("ampersand_right_split.txt", 'r').readlines()
    f = open("newfile3.txt".format(), 'w')
    for l in lines:
        if "&" in l:
            #param, value = str.split("?",1)
            mainurl,_, query = l.partition('?')
            queryvars = query.split("&")
            if len(l) == 0:
                break
            print l
            f.write(l)
    f.close()   

nestForLoop()

Answer 1

àlaClippy：“看起来你正在尝试解析网址”

来自the urlparse docs：

>>> from urlparse import urlparse
>>> o = urlparse('http://www.example.com/query%28%29.cgi?somevar=thing&someothervar=otherthing')
>>> o   
ParseResult(scheme='http', netloc='www.example.com', path='/query%28%29.cgi', params='', query='somevar=thing&someothervar=otherthing', fragment='')

所以，要将它与你的例子结合起来：

from urlparse import urlparse
def nestForLoop():
    lines = open("ampersand_right_split.txt", 'r').readlines()
    with open("newfile3.txt".format(), 'w') as f:

        for l in lines:
            url = urlparse(l)
            if url.query:
                #param, value = str.split("?",1)
                queryvars = url.query # Good to know, but why did we get this again?
                if len(l) == 0:
                    break
                print l
                f.write(l)

nestForLoop()

Answer 2

def nestForLoop():
lines = open("ampersand_right_split.txt", 'r').readlines()
f = open("newfile3.txt".format(), 'w')
g = open("newfile4.txt".format(), 'w')
for l in lines:
    if "&" in l:
        #param, value = str.split("?",1)
        mainurl,_, query = l.partition('?')
        queryvars = query.split("&")
        if len(l) == 0:
            break
        print l
        f.write(l)
        g.write(queryvars)
f.close()   
g.close()

有一种方法可以做到！

期待写出单独的文件;蟒蛇：

2 个答案: