Question

我想使用以前订单中的信息制作“畅销书”列表。我现在拥有的是这样的东西;

Product Quantity
2227    30
1722    3
1851    7
2227    10
1722    4
1863    1
etc....

第一列（产品）是每个产品的数据库中的唯一ID。数量当然是已售出的商品数量。每行用于一个订单。因此ID 2227在此列表中出现两次。

如何对此数据进行排序，以便总共获得ID 2227的销售次数？

我的PHP目前是：

$SQL_best = "SELECT c.company, co.id, cod.productId, cod.quantity 
FROM customers c 
LEFT JOIN customers_orders co ON c.id = co.custId 
LEFT JOIN customers_orders_details cod ON co.id = cod.orderId 
WHERE c.reseller =1 
AND c.status != 99 
AND c.id = ".$intCustomerId; 

$result_best = $objDB->sqlExecute($SQL_best);

*some html code here*

<table style="margin:0px auto;">
<tr>
    <th>Product</th>
    <th>Quantity</th>
</tr>
<?php
while($obj_best = $objDB->getObject($result_best)) {
    if ($obj_best->quantity > 0) { // don't include negatve quantaties (RMA's / refunds)
    echo "<tr>";
        echo "<td>".$obj_best->productId."</td>";
        echo "<td>".$obj_best->quantity."</td>";
    echo "</tr>";
    }
}
?>
</table>

MySQL查询

所以我需要将所有$obj_best->productId加在一起。在这种情况下我该怎么做？或者我应该编辑我的查询？

Answer 1

这是一个想法，你改变这样的SQL字符串：

$SQL_best = "SELECT c.company, co.id, cod.productId,
SUM(cod.quantity) AS quantity
FROM customers c 
LEFT JOIN customers_orders co ON c.id = co.custId 
LEFT JOIN customers_orders_details cod ON co.id = cod.orderId 
WHERE c.reseller = 1 
AND c.status != 99 
AND c.id = " . $intCustomerId . "
GROUP BY cod.productId
HAVING quantity > 0
ORDER BY quantity DESC";

如何制作畅销书清单？

1 个答案: