我想发布一个网址并保存到链接模型。但我得到了这个错误:
Category matching query does not exist
my views.py
def category_detail(request, category_name):
if request.POST:
form = CreateLinkForm(request.POST)
user = request.user
if form.is_valid():
link = form.save(commit=False)
link.user = user
link.category = Category.objects.get(name=category_name)
link.save()
return HttpResponseRedirect(reverse('category_detail', args=[category_name]))
else:
form = CreateLinkForm()
links = Link.objects.filter(category__name=category_name)
return render_to_response("category_detail.html", {"links":links, "form":form, "category_name":category_name}, context_instance=RequestContext(request))
当我在终端python manage.py shell查询时,我得到了这个:
>>> from link.models import Category
>>> Category.objects.all()
[<Category: <django.db.models.fields.related.ManyRelatedManager object at 0x22dbfd0> Programlama>, <Category: <django.db.models.fields.related.ManyRelatedManager object at 0x22de110> Foto>, <Category: <django.db.models.fields.related.ManyRelatedManager object at 0x22dbfd0> Sanat>]
>>> Category.objects.get(name="Foto")
<Category: <django.db.models.fields.related.ManyRelatedManager object at 0x22dbed0> Foto>
链接模型:
class Link(models.Model):
user = models.ForeignKey(User)
posted_at = models.DateTimeField(auto_now_add=True)
url = models.URLField()
title = models.CharField(max_length=255, null=True, blank=True)
category = models.ForeignKey(Category)
def __unicode__(self):
return "%s %s %s" %(self.url, self.title, self.category)
CreateLinkForm:
class CreateLinkForm(ModelForm):
class Meta:
model = Link
exclude = ["user", "posted_at", "category"]
那我错了什么?为什么我收到此错误Category matching query does not exist
答案 0 :(得分:0)
如果category_name
是您视图中的参数,并且您希望将其设置为link.category
,那么请在views.py
中执行此操作:
if form.is_valid():
...
link.category = category_name
...
# your other view code
view
错误输出的原因是你试图将字段设置为等于get()查询,但是Django期望在这里得到一个整数参数,因为你的category
字段Link
模型是Foreign Key
模型的Category
。