非常感谢任何帮助。

Question

我已编辑SQL以使用DISTINCT但是我仍然获得与使用GROUP BY时相同的数据。有什么建议？当我使用GROUP BY时，它要求包含select子句中的所有字段，有人能告诉我为什么会这样吗？

非常感谢任何帮助。

SELECT DISTINCT 
TrnClaim.ClientID
, TrnClaim.FileNo
, TrnLegend.RecordNo
, RTRIM(dbo.TrnClient.ClientName + ' ' + ISNULL(dbo.TrnClient.Initials,'') + ' ' +     (CASE WHEN dbo.TrnClient.LanguageCode = 'A' THEN ISNULL(dbo.TrnClient.Title, 'Mr') ELSE ISNULL(dbo.TrnClient.Title,'')END)) AS NameInitials
, TrnClient.IDNumber
, ISNULL(dbo.MstInsurer.InsurerName, 'Unknown') AS InsurerName
, CAST(dbo.TrnPolicy.AgentID AS VARCHAR(10)) + ' ' + ISNULL(CAST(dbo.MstAgent.AgentName AS VARCHAR(50)),'Unknown') AS AgentIDName
, CAST(dbo.TrnPolicy.TeamID AS VARCHAR(10)) + ' ' + ISNULL(dbo.VieTeamSelect.TeamName, 'Unknown') AS TeamIDName
, CAST(dbo.TrnPolicy.LinkID AS VARCHAR(10)) + ' ' + ISNULL(dbo.MstLink.LinkName, 'Unknown') AS LinkIDName
, CAST(dbo.TrnPolicy.SubagentID AS VARCHAR(10)) + ' ' + ISNULL(dbo.MstSubagent.SubagentName, 'Unknown') AS SubagentIDName
, CAST(dbo.TrnPolicy.MarketerID AS VARCHAR(10)) + ' ' + ISNULL(dbo.MstMarketerCodes.MarketerName, 'Unknown') AS MarketerIDName
, dbo.TrnRisk.RiskID
, dbo.TrnRisk.Registration
, dbo.TrnRisk.VehID
, dbo.TrnRisk.VinNo
, dbo.TrnRisk.VehMake
, dbo.TrnRisk.VehMake
, dbo.TrnRisk.VehModel
, dbo.TrnRisk.VehModel
, dbo.TrnExt.ExtStartDate
, dbo.TrnExt.ExtEndDate
, dbo.MstRateCodes.RateCodeID
, dbo.TrnExt.ExtDesc
, dbo.TrnPolicy.Status AS PolicyStatus
, dbo.TrnPolicy.PayMeth
, dbo.TrnPolicy.PolicyPeriod
, 1 AS [Count]
, dbo.TrnPolicy.TotalPrem AS LastMonthPremium
--, LastPolicy.TotalDue AS LastMonthTotalDue
, dbo.TrnPolicy.TeamID
, dbo.TrnPolicy.AgentID
, dbo.TrnPolicy.LinkID
, ISNULL(dbo.TrnPolicy.LeadInsurerID,MstInsurer.InsurerID) AS InsurerIDForFilter
, dbo.TrnLegend.LegendDescr
, dbo.TrnLegend.ActiveDate

FROM dbo.TrnClaim

INNER JOIN dbo.TrnPolicy ON
    TrnClaim.ClientID = dbo.TrnPolicy.ClientID 
    AND
    TrnClaim.FileNo = dbo.TrnPolicy.FileNo 

INNER JOIN dbo.TrnClient ON 
    dbo.TrnPolicy.ClientID = dbo.TrnClient.ClientID 

INNER JOIN dbo.TrnRisk ON 
    dbo.TrnPolicy.ClientID = dbo.TrnRisk.ClientID 
    AND 
    dbo.TrnPolicy.FileNo = dbo.TrnRisk.FileNo 

INNER JOIN dbo.TrnExt ON 
    dbo.TrnRisk.ClientID = dbo.TrnExt.ClientID 
    AND 
    dbo.TrnRisk.FileNo = dbo.TrnExt.FileNo 

LEFT OUTER JOIN dbo.MstRateCodes ON 
    dbo.MstRateCodes.RateCodeID = dbo.TrnExt.ExtCode    

LEFT OUTER JOIN dbo.MstInsurer MstInsurerLead ON 
    dbo.TrnPolicy.LeadInsurerID = MstInsurerLead.InsurerID 

LEFT OUTER JOIN dbo.TrnPolicy LastPolicy ON  
    dbo.TrnPolicy.ClientID = LastPolicy.ClientID 
    AND 
    dbo.TrnPolicy.FileNo = LastPolicy.FileNo 

LEFT OUTER JOIN dbo.MstAgent ON 
    dbo.TrnPolicy.AgentID = dbo.MstAgent.AgentID 

LEFT OUTER JOIN dbo.MstSubagent ON 
    dbo.TrnPolicy.SubagentID = dbo.MstSubagent.SubagentID 

LEFT OUTER JOIN dbo.MstMarketerCodes ON 
    dbo.TrnPolicy.MarketerID = dbo.MstMarketerCodes.MarketerID 

LEFT OUTER JOIN dbo.VieTeamSelect ON
    dbo.TrnPolicy.TeamID = dbo.VieTeamSelect.TeamID 

LEFT OUTER JOIN dbo.MstLink ON  
    dbo.TrnPolicy.LinkID = dbo.MstLink.LinkID 

LEFT OUTER JOIN dbo.MstInsurer ON 
    dbo.MstInsurer.InsurerID= dbo.TrnClaim.InsurerID

INNER JOIN dbo.TrnLegend On
    dbo.TrnLegend.ClientID = dbo.TrnClaim.ClientID
    AND
    dbo.TrnLegend.FileNo = dbo.TrnClaim.FileNo


WHERE 
Upper(dbo.TrnLegend.LegendDescr) LIKE '%CANCELLED%'

Order By 
dbo.TrnClaim.ClientID
, dbo.TrnClaim.FileNo
, dbo.TrnLegendRecordNo

Answer 1

使用Group By时，请指定属性列表。包含GROUP BY子句的查询会根据属于分组集的每个属性值的唯一组合，为每个组生成一行。

因此，在查询中指定GROUP BY时，所有后续步骤（HAVING，SELECT等）都只能指定每个组具有标量（奇异）值的表达式。这些表达式可以包括GROUP BY列表中的列或表达式，如TrnClaim.ClientID - 或聚合函数，例如COUNT（TrnClaim.ClientID）。

正如我所看到的，您在上面的查询中没有包含任何聚合函数，这就是为什么当你写下Group By（TrnClaim.ClientID）或任何其他列时，没有创建任何组或改写每一行成为一个唯一的组，所以它要求包含select子句中的所有字段。

这就是为什么您使用Distinct和GROUP BY获取相同数据的原因，因为没有创建任何组。

连续不同的错误

非常感谢任何帮助。

1 个答案: