我正在尝试制作两个下拉表单,其中第二个菜单中的信息会根据第一组选项中选择的内容而更改。到目前为止,我有两个下拉菜单,但我不知道如何使第二个依赖于第一个。任何帮助将非常感激。我正在使用csv文件来存储我的数据。这就是我到目前为止所做的:
<?php
$filename = ("florida.csv");
$csvfile = fopen($filename,'rb');
while(!feof($csvfile)) {
$csvarray[] = fgetcsv($csvfile);
}
print "<select>";
foreach($csvarray as $row => $arr) {
echo '<option value="' . $row . '">' . $arr[2] . $arr[0] . '</option>';
}
print "</select>";
print "<select>";
foreach($csvarray as $row => $arr) {
echo '<option value="' . $row . '">' . $arr[1] . '</option>';
}
print"</select>";
//print_r($csvarray);
?>
这是我的数组在我的csv文件中的样子。
[0] => Array
(
[0] => WNDT
[1] => 92.5 FM
[2] => Alachua
[3] => Ocala Broadcasting Corporation, L.L.C.
[4] => Classic Rock
[5] => Florida
)
[1] => Array
(
[0] => WORL
[1] => 660 AM
[2] => Altamonte Springs
[3] => Salem Media of Illinois, LLC
[4] => Sports
[5] => Florida
)
[2] => Array
(
[0] => WFCT
[1] => 105.5 FM
[2] => Apalachicola
[3] => Williams Communications, Inc.
[4] => Adult Standards
[5] => Florida
)
[3] => Array
(
[0] => WOYS
[1] => 100.5 FM
[2] => Apalachicola
[3] => 3G Broadcasting, Inc.
[4] => Classic Hits
[5] => Florida
)
[4] => Array
(
[0] => WBZW
[1] => 1520 AM
[2] => Apopka
[3] => Pennsylvania Media Associates, Inc.
[4] =>
[5] => Florida
)
[5] => Array
(
[0] => WFLN
[1] => 1480 AM
[2] => Arcadia
[3] => Integrity Radio of Florida LLC
[4] => News/Talk
[5] => Florida
)
答案 0 :(得分:0)
$state = isset($_POST['state']) ? $_POST['state'] : null;
echo "<select name='state'>";
foreach ($states as $key => $statename) {
echo "<option value='" . $key . "'" . ($key == $state ? ' selected' : '') . ">" . $statename . "</option>";
}
echo "</select>";
if (isset($state)) {
echo "<select name='city'>";
$csvarray = array();
$csvfile = fopen(strtolower(str_replace(' ', '', $states[$state])) . ".csv");
$row = 0;
while ($csvarray = fgetcsv($csvfile)) {
echo '<option value="' . $row . '">' . $arr[1] . '</option>';
}
echo "</select>";
}