Question

这可能是一个愚蠢的问题，不是一个完全与编程相关的问题，而是在我努力学习的过程中忍受。

FEEDLY如何通过在搜索框中输入网站网址来检索网站上的Feed /新闻。

例如，我在搜索字段中输入了http://www.inspirationfeed.com，并且传递的AJAX调用/查询字符串是

http://cloud.feedly.com/v3/search/feeds?q=http%3A%2F%2Finspirationfeed.com%2F&n=20&ck=1381664838936

它返回了一个JSON作为响应

{"results":[{"deliciousTags":["Design","inspiration","Diseño","Web Design","webdesign","graphic design"],"lastUpdated":1381561980000,"score":27531.265625,"website":"http://inspirationfeed.com","title":"inspirationfeed.com","subscribers":1772,"language":"en","velocity":16.3,"feedId":"feed/http://feeds.feedburner.com/inspirationfeed/BTLD","description":"be inspired!"},{"deliciousTags":["DESIGN","Inspiration"],"lastUpdated":1381474380000,"score":48.0,"website":"http://inspirationfeed.com","title":"inspirationfeed.com » Inspiration","subscribers":48,"language":"en","velocity":4.7,"feedId":"feed/http://inspirationfeed.com/category/inspiration/feed/","description":"be inspired!"},{"deliciousTags":["design"],"lastUpdated":1381479900000,"score":294.7439270019531,"website":"http://inspirationfeed.com","title":"inspirationfeed.com » Articles","subscribers":27,"language":"en","velocity":11.7,"feedId":"feed/http://inspirationfeed.com/category/articles/feed/","description":"be inspired!"},{"deliciousTags":["Photography"],"lastUpdated":1381129620000,"score":17.0,"website":"http://inspirationfeed.com","title":"inspirationfeed.com » Photography","subscribers":17,"language":"en","velocity":0.7,"feedId":"feed/http://inspirationfeed.com/category/photography/feed/","description":"be inspired!"},{"deliciousTags":["Little Bit of Everything-Amatuer"],"lastUpdated":1381396020000,"score":109.16442108154297,"website":"http://inspirationfeed.com","title":"inspirationfeed.com » Blogging","subscribers":10,"language":"en","velocity":0.5,"feedId":"feed/http://inspirationfeed.com/category/articles/blogging/feed/","description":"be inspired!"}]}

我理解的是什么

1）基于密钥deliciousTags，以feedly方式生成＃标签 2）根据密钥score，以自上而下的顺序排列网站提供的不同供稿/新闻网址

我没有理解

1）如何通过输入网站网址（示例： "feedId":"feed/http://feeds.feedburner.com/inspirationfeed/BTLD"）来获取新闻Feed / rss网址

2）需要为这样的事物编写什么类型的Web服务。是否需要服务器端脚本来深入搜索相关网站并检索提要URL？可以使用JQuery / Javascript在客户端本身获取提要URL吗？

再次感谢您花时间阅读问题。

Answer 1

在页面html的头部有一个带有rss / atom feed的网站链接，如下所示：

<link rel="alternate" type="application/atom+xml" title="Feed for question &#39;how does a service like feedly obtain the rss feeds from a website when the website URL is entered into the search box(not the feed url&#39;" href="/feeds/question/19345075">

这是此问题页面的来源

Feedly或类似服务搜索该页面的html（而不是主机），并找到此链接标记（使用rel，类型）：<link rel="alternate" type="application/atom+xml" title="awd" href="/feedUrl">或<link rel="alternate" type="application/rss+xml" title="awd" href="/feedUrl">（还有更多内容）

并且还有一些设置Feed网址的例程，

http://<url>/rss
http://<url>/feed
http://<url>/atom
http://<url>/<page>.xml

如果没有找到，那么那里什么都没有！

可以在服务器端和客户端完成，但在服务器端，在解析页面html和测试例程之前，还有更多好处，如数据库搜索。

默认情况下，Firefox有一个获取页面提要的选项，以前的chrome版本具有此类功能，但它已被谷歌（和谷歌方式）删除。（这是浏览器端，由用户控制和拥有，不能被网站使用！但你可以找到他们实现这种方法的方式）

当网站URL输入搜索框（而不是Feed网址）时，如何通过feedly从网站获取RSS订阅源的服务

1 个答案: