我真的被困在这上面了。我有一个名为“Example”的下拉菜单,其中包含2个子菜单“submenu1”和“submenu2”。单击2中的任何一个时,它将包含将以灯箱样式显示的图像拇指。但截至目前,两个拇指都显示出来,这不是我想要的,因为最终的网页将包含数百张图片。根据下面的代码,是否有办法只在单击一个子菜单时才显示图像。感谢
<!DOCTYPE html>
<head>
</head>
<body>
<!-- Portfolio Projects -->
<div class="row">
<div class="span3">
<!-- Filter -->
<nav id="options" class="work-nav">
<ul id="filters" class="option-set" data-option-key="filter">
<li class="type-work">CATEGORIES</li>
<li class="dropdown"><a data-toggle="dropdown" class="dropdown-toggle"
>BAPTISM
<b class="caret"></b></a>
<ul class="dropdown-menu">
<li class="dropdown-submenu">
<a href="#" class="selected">BOY CLOTHING</a>
<ul class="dropdown-menu">
<li><a href="#filter" data-option-
value=".boy" tabindex="-1">Clothing</a></li>
</ul>
</li>
<li class="dropdown-submenu">
<a href="#">GIRL CLOTHING</a>
<ul class="dropdown-menu">
<li><a href="#filter" data-option-
value=".girl" tabindex="-1">Clothing</a></li>
</ul>
</li>
</ul>
</li>
</ul>
</li>
</nav>
<script src="http://code.jquery.com/jquery.js"></script>
<script src="js/bootstrap.min.js"></script>
</ul>
</nav>
<!-- End Filter -->
</div>
<div class="span9">
<div class="row">
<section id="projects">
<ul id="thumbs">
<!-- gallery starts here -->
<li class="item-thumbs span3 boy"><!-- Fancybox - Gallery Enabled
- Title - Full Image -->
<a class="hover-wrap fancybox" data-fancybox-group="boy"
title="" href="_include/img/work/full/boy_clothing.jpg">
<span class="overlay-img"></span>
</a>
<!-- Thumb Image and Description -->
<img src="_include/img/work/thumbs/boy_clothing.jpg" alt="">
</li>
<li class="item-thumbs span3 girl">
<!-- Fancybox - Gallery Enabled - Title - Full Image -->
<a class="hover-wrap fancybox" data-fancybox-group="girl"
title="" href="_include/img/work/full/girl_clothing.jpg">
<span class="overlay-img"></span>
</a>
<!-- Thumb Image and Description -->
<img src="_include/img/work/thumbs/girl_clothing.jpg"
alt="">
</li>
</ul>
</section>
</div>
</div>
</div>
<!-- End Portfolio Projects -->
</body>
</html>
答案 0 :(得分:0)
这是我要做的: 我尝试保持逻辑简单,然后你可以在你的网站上使用类似的东西:)
(如果我错在这里,请S.O.纠正我!)
<强> CSS:强>
为您的子菜单提供ID
<强> JavaScript的:强>
// 2 event listeners that will run a function when the submenu is clicked:
var sub_menu_1 = document.getElementById( "submenu1" );
sub_menu_1.addEventListener("click", DISPLAY_menu_1 , false);
var sub_menu_2 = document.getElementById( "submenu2" );
sub_menu_2.addEventListener("click", DISPLAY_menu_1 , false);
function DISPLAY_menu_1 () {
// Do whatever CSS you need here, I simply make the entire DIV 'visible':
sub_menu_1.style.visibility = 'visible';
// For good measures, lets make submenu2 'invisible':
sub_menu_2.style.visibility = 'hidden';
}
function DISPLAY_menu_2 () {
// Same in Reverse
sub_menu_2.style.visibility = 'visible';
sub_menu_1.style.visibility = 'hidden';
}
修改强>
呼!这花了一段时间..对不起!
看看这个例子: 我基本上为你试了3个版本。
只需点击编辑此笔按钮即可查看代码!
答案 1 :(得分:0)
通过添加一个简单的单词,我无法相信我在这么多天后找到了解决方案。根本不必乱用javascript。实际上,在网站的外部.js 文件中,代码开发人员告诉我添加以下内容:过滤器:'。foobar'请参阅下面的最终结果{{1 }}