运行失败的java.util.NoSuchElementException

时间:2013-10-13 11:27:40

标签: java gradle

我正在建立并运行一个要求用户输入单词的java项目,当“完成”输入时,程序会打印一个已排序的字符串列表。

当我使用命令gradle -build构建项目时,它已成功构建,但是当我尝试运行它时,看起来Gradle没有“让我时间”输入一个单词,然后Gradle告诉我“找不到线路。”

以下是我的java程序中函数void enter_words()的摘录:

    System.out.println("Enter a word");
    str=sc.nextLine();

以下是Gradle在shell中使用gradle run命令时告诉我的内容:

C:\Users\celine\Desktop\test2>gradle run
:compileJava UP-TO-DATE
:processResources UP-TO-DATE
:classes UP-TO-DATE
:runMain
Enter a word // the program is running but I can't enter a word
Exception in thread "main" java.util.NoSuchElementException: No line found
        at java.util.Scanner.nextLine(Scanner.java:1585)
        at d.Project1.enter_words(Project1.java:42)
        at d.Project1.main(Project1.java:81)
:runMain FAILED

FAILURE: Build failed with an exception.

* What went wrong:
Execution failed for task ':runMain'.
> Process 'command 'C:\Program Files\Java\jdk1.7.0_40\bin\java.exe'' finished wi
th non-zero exit value 1

这是我的java程序:

package com.gumgum.test;

import java.util.Arrays;
import java.util.Scanner;

import org.apache.commons.lang.StringUtils;

public class Project1 {

    private int max;
    private String[] userInputs;

    // constructors
    public Project1() {
        max=100;
        userInputs = new String[max];
    }

    public Project1(int n) {
        max=n;
        userInputs = new String[max];
    }

    //getter
    String[] getUserInputs() {
        return userInputs;
    }

    //setter: all words entered by the users are written in tab
    public void setUserInputs(String[] tab, int position, String str) {
        tab[position]=str;
    }

    //demande à l'utilisateur d'entrer un mot
    public void enter_words () {
        Scanner sc = new Scanner(System.in);
        int countWords=0;
        String str="";
        while ((countWords<3) || (str.equals("done")!=true)) {

            System.out.println("Enter a word");
            str=sc.nextLine();

            if (StringUtils.isBlank(str) == true)
                    System.out.println("Please enter a valid word");
            else if (str.length()<=2) 
                System.out.println("Please enter at least 3 characters"); 

            if ((str.length()>=3) && (StringUtils.isBlank(str) != true)) {
                switch(str) {
                    case "done" :
                        if (countWords<3)
                            System.out.println("Please enter at least three words");
                        break;
                    default:
                        setUserInputs(this.userInputs,countWords,str);
                        countWords++;
                        break;
                }
            }
        }
    }

    public void lexico_order(String[] tab) {
        int i=0;
        System.out.println("");
        while(tab[i]!=null) {
            i++;
        }
        int k=0;
        Arrays.sort(tab, k, i);
        System.out.println("****** Sorted String List *******");
        for (int j=0;j<i;j++)
            System.out.println(tab[j]);
    }

    public static void main(String[] args) {
        Project1 p;
        p = new Project1();
        p.enter_words();
        System.out.printf("ca marche");
        p.lexico_order(p.getUserInputs());
    }

}

1 个答案:

答案 0 :(得分:4)

添加:

public function connect($apiUrl, $args, $response)
{
    try {
        $params = ['auth'  => [env('USERNAME'), env('PASSWORD')]];

        if ($response == 'get') {
            $params['query'] = $args;
        } else {
            $params['form_params'] = $args;
        }

        $apiResponse = $this->_restClient->request($response, env('URL') . env('PREFIX') . $apiUrl, $params)->getBody();

        return ($apiResponse == true) ? true : json_decode($apiResponse, true);
    } catch (RequestException $e) {
        if ($e->hasResponse()) throw new Exception($e->getMessage());
    }
}

到我的build.gradle为我解决了这个问题