使用以下代码段来访问带有帖子的网址。
我可以使用wget和以下内容获取它: wget --post-data'p_calling_proc = bwckschd.p_disp_dyn_sched& p_term = 201010'https://spectrumssb2.memphis.edu/pls/PROD/bwckgens.p_proc_term_date
由于某种原因,我的python文本有问题,因为我得到的错误代码为400.(当然浏览器按预期工作)
任何想法/评论等等......
我有的python测试:
// ==========================================
import urllib
import urllib2
import sys, string
import time
import mechanize
Request = urllib2.Request
urlopen = urllib2.urlopen
headers ={'User-Agent': 'Mozilla/4.0 (compatible; MSIE 5.5; Windows NT)'}
query = "p_calling_proc%3Dbwckschd.p_disp_dyn_sched%26p_term%3D201010"
url1="https://spectrumssb2.memphis.edu/pls/PROD/bwckgens.p_proc_term_date"
req = Request(url1, query, headers)
test1=0
test=0
while test==0:
print "aaaaattttt \n"
try:
res = urlopen(req)
#req = Request(url1, query, headers)
print "aaaappppp \n"
#urllib2.URLError, (e)
#print e
except urllib2.HTTPError, e:
print "ffff1111 "+str(e.code)+"\n"
if e.code:
test1=1
print "error ..sleep \n"
time.sleep(1)
else:
test1=0
except urllib2.URLError, e:
print e.reason
#print "ffff3333 "+e.code+"\n"
if e.reason:
test1=1
print "error ..sleep \n"
time.sleep(1)
else:
test1=0
#print "ddd "+e.code +"\n"
#print e
if test1==0:
test=1
print "test1 = "+str(test1)+"\n"
#res = urlopen(req)
print "gggg 000000000000\n"
s = res.read()
任何想法/意见将不胜感激..
感谢
答案 0 :(得分:1)
尝试不编码查询字符串。 POST数据中的&和s'不需要是urlencoded。如果远程端的Web应用程序不期望查询字符串中的%xx编码,则它将无法解析它。
这是curl的HTTP请求标头:
POST / HTTP/1.1
User-Agent: curl/7.19.4 (universal-apple-darwin10.0) libcurl/7.19.4 OpenSSL/0.9.8k zlib/1.2.3
Host: 127.0.0.1
Accept: */*
Content-Length: 188
Expect: 100-continue
bwckschd.p_disp_dyn_sched&p_term=201010
这是来自python的HTTP请求标头:
POST / HTTP/1.1
Accept-Encoding: identity
Content-Length: 60
Host: 127.0.0.1
Content-Type: application/x-www-form-urlencoded
Connection: close
User-Agent: Mozilla/4.0 (compatible; MSIE 5.5; Windows NT)
p_calling_proc%3Dbwckschd.p_disp_dyn_sched%26p_term%3D201010
答案 1 :(得分:0)
我认为您的查询字符串不太正确。尝试使用urllib.urlencode()方法生成查询,la
urllib.urlencode([ ('param1', value1), ('param2',value2) ])