我现在已经成功实现了我的GridView,但是,一如既往,整个ASP.NET生命周期的事情都困扰着我。我无法弄清楚为什么这不起作用。我已经将GridView的OnPageIndexChanged绑定为:
protected void GridView_PageIndexChanged(object sender, EventArgs e)
{
// Enable/disable the previous/next buttons.
LinkButton btnNextPage = (LinkButton)gvTable.BottomPagerRow.FindControl("btnNextPage");
LinkButton btnPreviousPage = (LinkButton)gvTable.BottomPagerRow.FindControl("btnPreviousPage");
btnNextPage.Enabled = false;
btnPreviousPage.Enabled = false;
}
这是我的ASCX:
<asp:GridView ID="gvTable" runat="server" ShowHeader="true" PageSize="1"
AllowPaging="true" AllowSorting="true" DataSourceID="dsLinqActivities"
AutoGenerateColumns="false" OnRowDataBound="GridView_DataBound"
OnPageIndexChanged="GridView_PageIndexChanged">
<Columns>
<asp:BoundField DataField="Edited" HeaderText="Date" />
<asp:BoundField DataField="Status" HeaderText="Status" />
<asp:BoundField DataField="Activity" />
</Columns>
<PagerSettings Position="Bottom" Visible="true" />
<PagerStyle CssClass="pager" />
<PagerTemplate>
<asp:LinkButton ID="btnPreviousPage" class="navbtn prev left"
runat="server" CommandName="Page" CommandArgument="Prev">
<span>Newer activities</span></asp:LinkButton>
<asp:LinkButton ID="btnNextPage" class="navbtn next right"
runat="server" CommandName="Page" CommandArgument="Next">
<span>Older activities</span></asp:LinkButton>
</PagerTemplate>
</asp:GridView>
我调试我的应用程序,看到代码正在运行并做正确的事情,但出于某种原因,当呈现控件时,两个按钮始终都是启用的。我在这里做错了什么?
答案 0 :(得分:2)
如果我是你,我会在“GridView_PageIndexChanged”方法中将其编码为
(gvTable.BottomPagerRow.FindControl("btnNextPage") as LinkButton).Enabled = true/false;
编辑:你还可以尝试添加一个setter吗?
set
{
gvTable.BottomPagerRow.FindControl("btnNextPage") as LinkButton =value;
}
编辑:好的,我的朋友,我终于找到了解决方案。可能不是很优雅,但它有效,我测试了它。有几件事需要注意: 1.我们有一个“上一个”和一个“下一个”按钮,我们必须处理“OnCommand”事件,因为我们使用自己的寻呼机模板 2.在处理OnCommand事件后,我们必须绑定数据。
我有一个静态List<String>
我在GET期间用随机字符串填充(Courtesy:http://www.kivela.be/index.php/2007/06/19/how-to-generate-a-random-string-in-c-20/)并将它们绑定到我的网格。您可以在此替换您自己的数据源。此外,我们必须在OnCommand事件中手动更改网格的页面索引。
这是我的aspx / ascx网格
<asp:GridView ID="GridView1" runat="server" OnRowDataBound="GridView_DataBound"
AllowPaging="true" PagerSettings-Mode="NextPrevious" PagerSettings-Position="Bottom" PageSize="10"
OnPageIndexChanged="GridView_PageIndexChanged">
<PagerSettings Position="Bottom" Visible="true" />
<PagerStyle CssClass="pager" />
<PagerTemplate>
<asp:LinkButton ID="btnPreviousPage" OnCommand="ChangePage"
runat="server" CommandName="Prev" Text="prev">
</asp:LinkButton>
<asp:LinkButton ID="btnNextPage" OnCommand="ChangePage"
runat="server" CommandName="Next" Text="next">
</asp:LinkButton>
</PagerTemplate>
</asp:GridView>
这是代码隐藏
public partial class TestPage : System.Web.UI.Page
{
private static Random _random = new Random();
static List<string> lst = new List<string>();
protected void Page_Load(object sender, EventArgs e)
{
if (!Page.IsPostBack)
{
for (int i = 1; i <= 30; i++)
{
lst.Add(RandomString(i));
}
GridView1.DataSource = lst;
GridView1.DataBind();
SetPageNumbers();
}
}
private void SetPageNumbers()
{
if (GridView1.PageIndex == 0)
{
(GridView1.BottomPagerRow.FindControl("btnPreviousPage")as LinkButton).Enabled = false;
}
if(GridView1.PageIndex ==GridView1.PageCount-1)
{
(GridView1.BottomPagerRow.FindControl("btnNextPage") as LinkButton).Enabled = false;
}
}
protected void ChangePage(object sender, CommandEventArgs e)
{
switch (e.CommandName)
{
case "Prev":
GridView1.PageIndex = GridView1.PageIndex - 1;
break;
case "Next":
GridView1.PageIndex = GridView1.PageIndex + 1;
break;
}
GridView1.DataSource = lst;
GridView1.DataBind();
SetPageNumbers();
}
public static string RandomString(int size)
{
StringBuilder builder = new StringBuilder();
for (int i = 0; i < size; i++)
{
//26 letters in the alfabet, ascii + 65 for the capital letters
builder.Append(Convert.ToChar(Convert.ToInt32(Math.Floor(26 * _random.NextDouble() + 65))));
}
return builder.ToString();
}
}
希望这有帮助
答案 1 :(得分:0)
您的CSS是否有可能设置启用的属性?
我没有CSS复制你的代码,它对我来说很好。
发布你的CSS怎么样?