我编码了一个搜索功能,但我总是得到1个结果!
有谁知道问题出在哪里?
<?PHP
if ($_SERVER['REQUEST_METHOD'] === 'POST') {
$sqlCmdSearch="SELECT * FROM name.name WHERE title LIKE '%".mysql_real_escape_string($_POST['search'])."%'";
$getSearch=mysql_query($sqlCmdSearch,$sqlHp);
while($getSearch = mysql_fetch_array($getSearch)) {
echo'<div id="main_item2">';
echo' <div class="main_image">';
echo' <a href="index.php?s=items&id='.$getSearch["id"].'"><img src="www/img/thumbs/'.$getSearch["image"].'"></a>';
echo' </div>';
echo' <div class="title_list">';
echo' <a href="index.php?s=items&id='.$getSearch["id"].'">'.$getSearch["title"].'</a>';
echo' </div>';
echo' <div class="description_list"> ';
echo' <p>'.$getSearch["description"].'</p>';
echo' </div>';
echo' <div class="button_list">';
echo' <p>Price: '.$getSearch["item_price"] .' '.$getSearch["currency"].'</p>';
echo' <span style="padding-left:15px;"><a href="index.php?s=items&id='.$getSearch["id"].'" class="button">Watch Item</a></span>';
echo' </div>';
echo'</div>';
}
}
else{
echo '<p>Search failed please try again.</p>';
}
?>
我已经尝试了一切,但没有任何帮助..
答案 0 :(得分:2)
您正在覆盖您的mysql结果变量
所以请替换以下代码:
$getSearch=mysql_query($sqlCmdSearch,$sqlHp);
while($getSearch = mysql_fetch_array($getSearch)) {
这个:
$getSearch_set=mysql_query($sqlCmdSearch,$sqlHp);
while($getSearch = mysql_fetch_array($getSearch_set)) {