我在做一些测试时遇到过这个问题。我提出了一个名为ModalView1的模态视图。在ModalView1中,当按下某个按钮时,将使用presentViewController
显示另一个名为ModalView2的模态视图。然后我尝试使用dismissViewControllerAnimated
解雇ModalView2,但它无法正常工作。
这是按钮操作中的代码片段
- (void) buttonAction: (UIButton*) sender
{
ModalView *ModalView2 = [[ModalView alloc] init];
[self presentViewController:ModalView2 animated:YES completion:nil];
[self dismissViewControllerAnimated:YES completion:nil];
}
非常感谢任何帮助。谢谢。
答案 0 :(得分:5)
目前尚不清楚你要做什么。我给你两个选择:
呈现ModalView2然后解雇ModalView2(对我没用,但这就是我在你的问题中可以阅读的内容)
- (void) buttonAction: (UIButton*) sender {
ModalView* modalView2 = [[ModalView alloc] init];
[self presentViewController:modalView2 animated:YES completion:^{
[modalView2 dismissViewControllerAnimated:YES completion:nil];
}];
}
演示ModalView2并解散ModalView1:
- (void) buttonAction: (UIButton*) sender {
ModalView* modalView2 = [[ModalView alloc] init];
UIViewController* presentingViewController = self.presentingViewController;
[self dismissViewControllerAnimated:YES completion:^{
[presentingViewController presentViewController:modalView2 animated:YES completion:nil];
}];
}
答案 1 :(得分:1)
在现在的时候,不要打电话给所以给点时间
试试这个让我工作
- (void) buttonAction: (UIButton*) sender
{
[self performSelector:@selector(call) withObject:nil afterDelay:.4];
[self dismissViewControllerAnimated:YES completion:nil];
}
-(void)call
{
ModalView *ModalView2 = [[ModalView alloc] init];
[self presentViewController:ModalView2 animated:YES completion:nil];
}