Question

我正在研究我的中期项目，而且我或多或少已经完成了。我遇到的唯一问题是，当我运行程序并要求我输入完整员工的姓名时，编译器会向我抛出有关扫描程序的异常。我从Scanner输入到＆＃34; scanner user_input＆＃34;但它仍然无法正确编译。任何关于问题的提示都将受到赞赏。

package midterm;

import java.util.Scanner;

public class Midterm {

    public static void main(String[] args) {
        Scanner user_input = new Scanner(System.in);

        System.out.print("If you wish to enter another's employee's inforamtion"
                        + " please press 1, else to exit enter 0.");
        int choice = user_input.nextInt();

        if (choice == 1) {
            System.out.print("What is the employee's full name. ");
            String empName = user_input.next();
            System.out.printf("Please enter the number of hours that the employee has worked. ");
            double hoursWorked = user_input.nextDouble();
            System.out.printf("Please enter the employee's hourly pay rate. ");
            double payRate = user_input.nextDouble();

            displayPay(empName, calculatePay(hoursWorked, payRate));
        }
        else if (choice == 0) {
            System.exit(0);
        }
    }

    public static double calculatePay(double hours, double pay) {
        double wages = 0;

        if (hours <= 40) {
            wages = hours * pay;
        }

        if (hours > 40) {
            double regPay = hours * pay;
            double overTime = (hours - 40) * pay * 1.5;
            wages = regPay + overTime;
        }

        return wages;
    }

    public static void displayPay(String name, double empWage) {
        System.out.print("-----------------------------------------");
        System.out.print("Employee Name: " + name);
        System.out.print("Pay Check Amount: $" + empWage);
        System.out.print("-----------------------------------------");
    }
}

Answer 1

错误在于：

System.out.print ("What is the employee's full name. ");
String empName = user_input.next();

next()读取所有内容，直到下一个分隔符，默认为空格。因此，如果有人输入名字和姓氏（以空格分隔），则只会读取名字。因此，当您稍后调用user_input.nextDouble()时，仍然会读取部分名称，并且程序因为下一个标记（在本例中为姓氏）而无法解析为{{1 }}

由于这听起来像是一个学校项目，我不会确切地说如何修复它。

Answer 2

尝试使用：

System.out.print ("What is the employee's full name. ");
String empName = user_input.nextLine();

Answer 3

请勿使用user_input.next();

而不是那样，试试这个：user_input.nextLine();

Answer 4

非常直接！这是您可以使用scanner类接受键盘输入的方法：

    String str;
    Scanner in = new Scanner(System.in);

    System.out.println("Enter any string :-");
    str = in.nextLine();
    System.out.println(str); // will print the string that you entered.

Java扫描程序异常问题

4 个答案: