我有这个问题:
set @last_uid = 0;
set @last_tm = '00:00';
set @last_vid = 0;
SELECT v.*,
CASE WHEN @last_uid = visitorid AND cast( @last_tm as datetime) >= subtime( timestamp, '01:00' )
THEN
if( (@last_tm := timestamp ), @last_vid, @last_vid)
ELSE
if( (@last_uid := visitorid) + (@last_vid := @last_vid+1) +(@last_tm := timestamp ),@last_vid, @last_vid )
END AS newVisitID
FROM visits v
ORDER BY timestamp DESC, visitorid
我尝试在WHERE子句中使用newVisitID列,如下所示:
WHERE newVisitID <=5
这给了我错误:
#1054 - Unknown column 'newVisitID' in 'where clause'
有人可以帮我解决这个问题吗?
答案 0 :(得分:5)
您无法在WHERE
子句中引用别名,但可以在HAVING
中引用它们:
SELECT v.*,
CASE WHEN @last_uid = visitorid AND cast( @last_tm as datetime) >= subtime( timestamp, '01:00' )
THEN
if( (@last_tm := timestamp ), @last_vid, @last_vid)
ELSE
if( (@last_uid := visitorid) + (@last_vid := @last_vid+1) +(@last_tm := timestamp ),@last_vid, @last_vid )
END AS newVisitID
FROM visits v
HAVING newVisitID <- 5
ORDER BY timestamp DESC, visitorid
答案 1 :(得分:2)
您可以再次写出case语句,或者更简单的方法是将其包装然后过滤子查询:
select * from
(
SELECT v.*,
CASE WHEN @last_uid = visitorid AND cast( @last_tm as datetime) >= subtime( timestamp, '01:00' )
THEN if( (@last_tm := timestamp ), @last_vid, @last_vid)
ELSE if( (@last_uid := visitorid) + (@last_vid := @last_vid+1) +(@last_tm := timestamp ),@last_vid, @last_vid )
END AS newVisitID
FROM visits v
) x
WHERE x.newVisitID <= 5
ORDER BY x.timestamp DESC, x.visitorid
答案 2 :(得分:1)
认为你可以使用变量
SELECT v.*,
@newVisitID := CASE WHEN @last_uid = visitorid AND cast( @last_tm as datetime) >= subtime( timestamp, '01:00' )
THEN
if( (@last_tm := timestamp ), @last_vid, @last_vid)
ELSE
if( (@last_uid := visitorid) + (@last_vid := @last_vid+1) +(@last_tm := timestamp ),@last_vid, @last_vid )
END AS newVisitID
FROM visits v
where @newVisitID <= 5
ORDER BY timestamp DESC, visitorid
如果您不想重复代码,请使用子查询。