SQL:按最近逗号分隔的日期排序

时间:2013-10-11 22:11:35

标签: sql sql-server sql-server-2008-r2

我有一个表格,日期以逗号分隔,如下所示

9/30/2013,9/17/2013,10/16/2013,
5/27/2013, 9/30/2013,
09/24/2013,09/27/2013,
09/13/2013,11/18/2013,
09/11/2013,09/13/2013,
12/27/2013,12/20/2013,
12/27/2013,12/20/2013,12/13/2013,12/6/2013,11/29/2013,
10/3/2013,10/10/2013,10/17/2013,10/24/2013,10/31/2013,
10/31/2013,10/24/2013,10/17/2013,10/10/2013,10/3/2013,

现在我的任务是对最近的第一个记录进行排序,过去的日期可以忽略。需要将所有日期与当前日期进行比较,请建议我如何实现此目标

提前致谢。

已编辑

我除外:

9/30/2013,9/17/2013,10/16/2013, as 10/16/2013 is nearest of all
10/3/2013,10/10/2013,10/17/2013,10/24/2013,10/31/2013, as 10/17/2013 next nearest
10/31/2013,10/24/2013,10/17/2013,10/10/2013,10/3/2013,
12/27/2013,12/20/2013,12/13/2013,12/6/2013,11/29/2013,
12/27/2013,12/20/2013,    

1 个答案:

答案 0 :(得分:0)

这是一个将字符串转换为日期表的udf:

CREATE FUNCTION [dbo].[udf_ConvertCSVStringToDateTable] 
(
    @CSVString varchar(max)
)
RETURNS 
@DateTable TABLE 
(
    [Date] DATETIME
)
AS
BEGIN
    DECLARE @ListSize BIGINT
    DECLARE @FoundIndex BIGINT
    DECLARE @Date INT
    DECLARE @DateString VARCHAR(10)

    SET @ListSize = LEN(@CSVString)

    WHILE(@ListSize > 0)
    BEGIN
        SET @FoundIndex = CHARINDEX(',', @CSVString)

        IF(@FoundIndex = 0)
        BEGIN
            SET @DateString = @CSVString
            SET @CSVString = ''
        END
        ELSE
        BEGIN
            SET @DateString = SUBSTRING(@CSVString, 1, @FoundIndex - 1)
            SET @CSVString = SUBSTRING(@CSVString, @FoundIndex + 1, @ListSize) 
        END

        IF(ISDATE(@DateString) = 1)
        BEGIN
            INSERT @DateTable([Date]) VALUES (CONVERT(DATETIME, @DateString))
        END

        SET @ListSize = LEN(@CSVString)
    END
    RETURN 
END

从那以后你应该可以使用WHERE子句进行选择和过滤,或者使用ORDER BY子句进行排序