Question

美好的一天。

数据库：MySQL

表格

name (varchar 200)
status (enum 'open','close','pause')

要获取所有name的所有状态，我需要使用4个查询：

SELECT count(*) FROM TABLE //count all names
SELECT count(*) FROM TABLE where status = open //count names where status = open
SELECT count(*) FROM TABLE where status = close //count names where status = close
SELECT count(*) FROM TABLE where status = pause //count names where status = pause

任何人都知道如何在一个 sql查询中获得所有重要信息吗？

Answer 1

SELECT count(*) as total_count,
       sum(status = 'open') as status_open_count,
       sum(status = 'close') as status_close_count,
       sum(status = 'pause') as status_pause_count
FROM TABLE

Answer 2

使用以下查询：

SELECT status, count(name) as cnt FROM TABLE GROUP BY status;

Answer 3

你可以尝试

Select Count(Status),Status,(Select Count(Status) as TotalCount From TABLE) From TABLE Group By Status;

Answer 4

另一种选择： -

SELECT status, COUNT(*) as aCount,
FROM TABLE
GROUP BY status
UNION ALL 
SELECT 'All', COUNT(*) as aCount,
FROM TABLE

可以在一个SQL查询中获得一些计数吗？

4 个答案: