如何在PowerShell中使用带有命名空间的xpath访问元素?

时间:2013-10-11 01:49:59

标签: xml powershell xpath xml-namespaces

Powershell的:

$doc = new-object System.Xml.XmlDocument
$doc.Load($filename)

$items = Select-Xml -Xml $doc -XPath '//item'
$items | foreach {
    $item = $_
    write-host $item.name
}

我没有输出

XML:

<?xml version="1.0" encoding="UTF-8"?>
<submission version="2.0" type="TREE" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:noNamespaceSchemaLocation="TREE.xsd" xmlns="some/kind/of/tree/v1">
  <group>
    <item></item>
    <item></item>
    <item></item>
  </group>
<submission>

1 个答案:

答案 0 :(得分:11)

你有一些问题在继续。首先,您需要在XPath模式中指定命名空间,XML格式不正确(结束标记不是结束标记),而Select-Xml直接返回XmlInfo而不是XmlElement。试试这个:

$xml = [xml]@'
<submission version="2.0" type="TREE" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:noNamespaceSchemaLocation="TREE.xsd" xmlns="some/kind/of/tree/v1">
  <group>
    <item></item>
    <item></item>
    <item></item>
  </group>
</submission>
'@

$ns = @{dns="some/kind/of/tree/v1"}
$items = Select-Xml -Xml $xml -XPath '//dns:item' -Namespace $ns
$items | Foreach {$_.Node.Name}