我正在查询数据库,以找到系统中所有客户的最高收入月份。我的查询工作是为了从客户数据存在的所有年份中获取每月收入。但是我很难弄清楚如何从这些数据中获得最高的收入。
数据库是SQL Server 2008 R2。 列为:客户名称,年份,月份和收入。 我甚至尝试使用Row_Number()并尝试按客户名称/年分区并按收入排序。但它没有用。也许我在那里犯了一些错误。
以下是我尝试构建基本查询的方法。
Select Customer, Year(orderdatetime) as Year, Month(orderdatetime) as Month, SUM(Revenue)
From Orders
Group By Customer, Year(orderdatetime), Month(orderdatetime)
这就是我尝试使用Row_Number()
的方法WITH Max_Revenue AS
(
Select Customer, Year(orderdatetime) as Year, Month(orderdatetime) as Month, SUM(Revenue), RowNumber = ROW_NUMBER() OVER(PARTITION By Year Order By Revenue DESC)
From Orders
Group By Customer, Year(orderdatetime), Month(orderdatetime)
)
Select Max_Revenue.Customer, Max_Revenue.Year, Max_Revenue.Month, Max_Revenue.Revenue
From Max_Revenue
Where Max_Revenue.RowNumber = 1
Order By Max_Revenue.Customer asc
我得到的数据如下:
Customer Month Year Revenue
ABC 2 2012 100
ABC 3 2013 150
ABC 5 2012 200
XYZ 4 2011 500
XYZ 6 2012 650
XYZ 7 2012 800
我想要的输出是什么
Customer Month Year Revenue
ABC 5 2012 200
XYZ 7 2012 800
因此,每个客户的最佳月份和各年的收入。
答案 0 :(得分:1)
SELECT Customer,
Year,
Revenue,
Month
FROM (
SELECT Customer,
Year,
ROW_NUMBER() OVER(PARTITION By Customer Order By Revenue DESC) as rank,
Revenue,
Month
FROM (
Select Customer,
Year(orderdatetime) as Year,
Month(orderdatetime) as Month,
SUM(Revenue) as Revenue
From Orders
Group By
Customer,
Year(orderdatetime),
Month(orderdatetime)
) BS
GROUP BY Customer,
Year,
Month) BS2
WHERE BS2.rank = 1
OR change = ROW_NUMBER()OVER(按年份划分按收入DESC到 = ROW_NUMBER()OVER(按收入DESC划分客户订单