Question

我不是一个完整的新手，所以我明白这意味着什么等等，但我似乎无法弄清楚Eclipse似乎认为我错过了什么神秘的支架。

（忽略这样一个事实，即我没有构建我所说的我将在我的代码中构建的东西 - 我还没有那么远。）

#include "./BinaryTree.h"
using namespace ods;
typedef BTNode1 Node;
Node * buildNode(Node *p = NULL, Node *l = NULL, Node *r = NULL) {
    Node * ans = new Node;
    ans->parent = p; ans->left = l; ans->right = r;
    return ans;
}

typedef BTNode1 Node;
Node * buildNodeComplete(Node *p = NULL, Node*l = NULL, Node *r = NULL) {
    Node * ans = new Node;
    ans->parent = p; ans->left = l; ans->right = r;
    return ans;
}

typedef BTNode1 Node;
Node * buildNodeStringy(Node *p = NULL, Node*l = NULL, Node *r = NULL) {
    Node * ans = new Node;
    ans->parent = p; ans->left = l; ans->right = r;
    return ans;
}

int main() {
    // build random tree of 1023 nodes
    BinaryTree<Node> T;
    Node *u;
    T.root() = buildNode();
    int d;

    for (int i = 1; i < 1023; ++i) {
        T.randomWalk(u, d);
        if (d == 0) u->left = buildNode(u);
        else u->right = buildNode(u);
    }

    //build complete tree of 1023 nodes
    BinaryTree<BTNode1> C;
    Node *a;
    C.root() = buildNodeComplete();
    int g;

    for (int i = 1; i <1023; i++) {
        C.randomWalk(a, g);
        if (g == 0) a->left = buildNodeComplete(a);
        else a->right = buildNodeComplete(a);
    }

    //build stringy tree of 1023 nodes
    BinaryTree<Node> S;
    Node *q;
    S.root() = buildNodeStringy();
    int v;

    for (int i = 1; i <1023; i++) {
         S.randomWalk(q, v);
         if (v == 0) q->left = buildNodeStringy(q);
         else q->right = buildNodeStringy(q);
    }

    // measure random walks in T
    double sum=0;
    double sum1=0;
    double sum2=0;
    for (int i = 0; i < 1000; ++i) {
        T.randomWalk(u, d);
        sum += T.depth(u);
        C.randomWalk(a, g);
        sum1 += C.depth(a);
        S.randomWalk(q, v);
        sum2 += S.depth(q);
    }

    std::cout << "Average length of random walk through arbitrary tree is "
              << sum/1000;
    std::cout << " and lg(n+1) = lg(1024) = 10."
              << std::endl;

   //lab 5 part b
    std::cout << "Average length of random walk through complete tree is "
              << sum1/1000 << endl;
    std::cout << "Average length of random walk through stringy tree is "
              << sum2/1000;

    return 0;
}

Answer 1

据说this bug in Eclipse fixed，但尝试在封闭的括号后面添加一个新行。过去需要在.cpp文件的末尾添加一个新行字符，但现在实际上并不是必需的。

此外，如果我见过一个，这看起来像是数据结构类的分配，所以好运（在它变得更容易之前变得更难。）

＆＃34;预期＆＃39;}＆＃39;在输入结束时＃34;。为什么我一直收到这个错误？

1 个答案: