从.Bundle开始捕获名字

Question

我输入了

/System/Library/CoreServices/AOS.bundle/Contents/version.plist 
/System/Library/CoreServices/Br.bundle/Contents/Resources/brtool 
/System/Library/CoreServices/backupd.bundle/Contents/PlugIns/brtools.bundles/Contents/Version.plist

我需要输出 （.bundle首次发生的文本）

/System/Library/CoreServices/AOS.bundle
/System/Library/CoreServices/Br.bundle
/System/Library/CoreServices/backupd.bundle

Answer 1

awk的一种方式：

$ awk '{print $1 FS}' FS='.bundle' file
/System/Library/CoreServices/AOS.bundle
/System/Library/CoreServices/Br.bundle
/System/Library/CoreServices/backupd.bundle

仅适用于包含.bundle的行：

$ awk '$0~FS{print $1 FS}' FS='.bundle' file
/System/Library/CoreServices/AOS.bundle
/System/Library/CoreServices/Br.bundle
/System/Library/CoreServices/backupd.bundle

Answer 2

使用sed：

sed 's/\(\.bundle\).*$/\1/' Input

Answer 3

尝试sed 's=bundle/.*=bundle='。

Answer 4

使用egrep -o

 grep -oP '.*?\.bundle(?=/)' file

/System/Library/CoreServices/AOS.bundle
/System/Library/CoreServices/Br.bundle
/System/Library/CoreServices/backupd.bundle

工作演示：http://ideone.com/iT6VGy

Answer 5

这是一个正则表达式匹配，包含用于python的组：http://regex101.com/r/yL3xZ5

以下是awk

的简单示例

❯ awk '/\.bundle/{ gsub(/\.bundle\/.*$/, ".bundle"); print; }' <<_EOF_
/System/Library/CoreServices/AOS.bundle/Contents/version.plist
/System/Library/CoreServices/Br.bundle/Contents/Resources/brtool
/System/Library/CoreServices/backupd.bundle/Contents/PlugIns/brtools.bundles/Contents/Version.plist
_EOF_
/System/Library/CoreServices/AOS.bundle
/System/Library/CoreServices/Br.bundle
/System/Library/CoreServices/backupd.bundle
❯

sed中的另一个：

❯ sed -e 's@\(\.bundle\)/.*$@\1@' <<_EOF_
/System/Library/CoreServices/AOS.bundle/Contents/version.plist
/System/Library/CoreServices/Br.bundle/Contents/Resources/brtool
/System/Library/CoreServices/backupd.bundle/Contents/PlugIns/brtools.bundles/Contents/Version.plist
_EOF_
/System/Library/CoreServices/AOS.bundle
/System/Library/CoreServices/Br.bundle
/System/Library/CoreServices/backupd.bundle
❯

另一个纯bash：

❯ while read line; do echo ${line/.bundle\/*/.bundle}; done <<_EOF_
/System/Library/CoreServices/AOS.bundle/Contents/version.plist
/System/Library/CoreServices/Br.bundle/Contents/Resources/brtool
/System/Library/CoreServices/backupd.bundle/Contents/PlugIns/brtools.bundles/Contents/Version.plist
_EOF_

/System/Library/CoreServices/AOS.bundle
/System/Library/CoreServices/Br.bundle
/System/Library/CoreServices/backupd.bundle
❯

最后一个，grep

❯ grep -oP '^(.*?\.bundle)(?=/)' <<_EOF_
/System/Library/CoreServices/AOS.bundle/Contents/version.plist
/System/Library/CoreServices/Br.bundle/Contents/Resources/brtool
/System/Library/CoreServices/backupd.bundle/Contents/PlugIns/brtools.bundles/Contents/Version.plist
_EOF_

/System/Library/CoreServices/AOS.bundle
/System/Library/CoreServices/Br.bundle
/System/Library/CoreServices/backupd.bundle
❯