指定的子项已有父项。您必须首先在孩子的父母上调用removeView（）

Question

我创建这篇文章，因为我是新手，我需要一些帮助。我正在做一个关于你的名字的应用程序的一个小练习，它返回“你好（你放的名字）”。但是在我按下按钮后我得到错误“指定的孩子已经有了父母。你必须首先在孩子的父母上调用removeView（）”

MainActivity.java

package com.example.holaamigos;

import android.os.Bundle;
import android.app.Activity;
import android.content.Intent;
import android.view.*;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.EditText;

public class MainActivity extends Activity {
    public final static String EXTRA_SALUDO = "com.example.holaamigos.SALUDO";

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        final EditText txtNombre = (EditText)findViewById(R.id.TxtNombre);
        final Button btnHola = (Button)findViewById(R.id.BtnHola);

            btnHola.setOnClickListener(new OnClickListener() {
                @Override
                public void onClick(View v) {
                    Intent intent = new Intent(MainActivity.this, ActivitySaludo.class);
                    String saludo = txtNombre.getText().toString();
                    intent.putExtra(EXTRA_SALUDO, saludo);
                    startActivity(intent);
        }

    });

    }

    @Override
    public boolean onCreateOptionsMenu(Menu menu) {
        // Inflate the menu; this adds items to the action bar if it is present.
        getMenuInflater().inflate(R.menu.main, menu);
        return true;
    }

}

ActivitySaludo.java

package com.example.holaamigos;


import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.widget.TextView;

public class ActivitySaludo extends Activity {

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_saludo);

        Intent intent = getIntent();
        String saludo = intent.getStringExtra(MainActivity.EXTRA_SALUDO);

        //TextView txt = new TextView(this);
        //txt.setText(20);
        //txt.setText(saludo);

        TextView txtCambiado = (TextView) findViewById(R.id.TxtSaludo);
        txtCambiado.setText(saludo);
        setContentView(txtCambiado);
    }

}

activity_saludo.xml

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:orientation="vertical" >

    <TextView 
        android:id="@+id/TxtSaludo"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:text="" />


</LinearLayout>

activity_main.xml中

<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tools="http://schemas.android.com/tools"
    android:id="@+id/LinearLayout1"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:orientation="vertical" >

    <TextView
        android:id="@+id/LblNombre"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:text="@string/nombre" />

    <EditText
        android:id="@+id/TxtNombre"
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:inputType="text" />

    <Button 
        android:id="@+id/BtnHola"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:text="@string/hola_apy"
        android:onClick="enviarSaludo"/>

</LinearLayout>

logcat的

10-10 16:12:18.470: D/AndroidRuntime(810): Shutting down VM
10-10 16:12:18.470: W/dalvikvm(810): threadid=1: thread exiting with uncaught exception (group=0x40a71930)
10-10 16:12:18.586: E/AndroidRuntime(810): FATAL EXCEPTION: main
10-10 16:12:18.586: E/AndroidRuntime(810): java.lang.RuntimeException: Unable to start activity ComponentInfo{com.example.holaamigos/com.example.holaamigos.ActivitySaludo}: java.lang.IllegalStateException: The specified child already has a parent. You must call removeView() on the child's parent first.
10-10 16:12:18.586: E/AndroidRuntime(810):  at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2180)
10-10 16:12:18.586: E/AndroidRuntime(810):  at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:2230)
10-10 16:12:18.586: E/AndroidRuntime(810):  at android.app.ActivityThread.access$600(ActivityThread.java:141)
10-10 16:12:18.586: E/AndroidRuntime(810):  at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1234)
10-10 16:12:18.586: E/AndroidRuntime(810):  at android.os.Handler.dispatchMessage(Handler.java:99)
10-10 16:12:18.586: E/AndroidRuntime(810):  at android.os.Looper.loop(Looper.java:137)
10-10 16:12:18.586: E/AndroidRuntime(810):  at android.app.ActivityThread.main(ActivityThread.java:5041)
10-10 16:12:18.586: E/AndroidRuntime(810):  at java.lang.reflect.Method.invokeNative(Native Method)
10-10 16:12:18.586: E/AndroidRuntime(810):  at java.lang.reflect.Method.invoke(Method.java:511)
10-10 16:12:18.586: E/AndroidRuntime(810):  at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:793)
10-10 16:12:18.586: E/AndroidRuntime(810):  at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:560)
10-10 16:12:18.586: E/AndroidRuntime(810):  at dalvik.system.NativeStart.main(Native Method)
10-10 16:12:18.586: E/AndroidRuntime(810): Caused by: java.lang.IllegalStateException: The specified child already has a parent. You must call removeView() on the child's parent first.
10-10 16:12:18.586: E/AndroidRuntime(810):  at android.view.ViewGroup.addViewInner(ViewGroup.java:3339)
10-10 16:12:18.586: E/AndroidRuntime(810):  at android.view.ViewGroup.addView(ViewGroup.java:3210)
10-10 16:12:18.586: E/AndroidRuntime(810):  at android.view.ViewGroup.addView(ViewGroup.java:3186)
10-10 16:12:18.586: E/AndroidRuntime(810):  at com.android.internal.policy.impl.PhoneWindow.setContentView(PhoneWindow.java:289)
10-10 16:12:18.586: E/AndroidRuntime(810):  at com.android.internal.policy.impl.PhoneWindow.setContentView(PhoneWindow.java:279)
10-10 16:12:18.586: E/AndroidRuntime(810):  at android.app.Activity.setContentView(Activity.java:1901)
10-10 16:12:18.586: E/AndroidRuntime(810):  at com.example.holaamigos.ActivitySaludo.onCreate(ActivitySaludo.java:25)
10-10 16:12:18.586: E/AndroidRuntime(810):  at android.app.Activity.performCreate(Activity.java:5104)
10-10 16:12:18.586: E/AndroidRuntime(810):  at android.app.Instrumentation.callActivityOnCreate(Instrumentation.java:1080)
10-10 16:12:18.586: E/AndroidRuntime(810):  at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2144)
10-10 16:12:18.586: E/AndroidRuntime(810):  ... 11 more
10-10 16:12:18.856: D/dalvikvm(810): GC_CONCURRENT freed 134K, 10% free 2630K/2908K, paused 73ms+83ms, total 237ms

Answer 1

每当我在onCreateView()方法中为片段的视图膨胀时，只要我省略了参数，就会遇到此错误：

public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
    View view=inflater.inflate(R.layout.fragment_reject, container);
    return view;
}

解决方案是将视图通胀线更改为：

View view=inflater.inflate(R.layout.fragment_reject, container,false);

可以在Android guide for fragments

找到解释

从指南中引用，视图初始化语句中的最后一个参数为false，因为：

  

“系统已经将膨胀的布局插入到容器中 - 传递true将在最终布局中创建冗余视图组”

Answer 2

onCreate with activity或onCreateView with fragment

 if (view != null) {
    ViewGroup parent = (ViewGroup) view.getParent();
    if (parent != null) {
        parent.removeView(view);
    }
}
try {
    view = inflater.inflate(R.layout.fragment_main, container, false);
} catch (InflateException e) {

}

Answer 3

在ActivitySaludo，这一行，

    setContentView(txtCambiado);

您必须只为活动设置一次内容视图。

Answer 4

你不需要这一行：setContentView(txtCambiado);

Answer 5

在我的情况下，我意外地从Layout.onCreateView()内返回了一个子视图，如下所示：

public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
    View view = inflater.inflate(R.layout.fragment_reject, container, false);

    Button button = view.findViewById(R.id.some_button);

    return button; // <-- Problem is this
}

解决方案是返回父视图而不是子视图。

Answer 6

请尝试这种方式，希望这有助于您解决问题。

TextView textView = new TextView(this);
textView.setText("CustomTextView");
addContentView(textView,new ViewGroup.LayoutParams(ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT));

Answer 7

如果要在for循环中重复添加相同的视图..如果是这种情况，则尝试在for循环内创建布局的View对象。 并在for循环中添加视图

避免此类问题

Answer 8

在我的情况下，问题是我试图多次将相同的视图添加到线性布局

View childView = LayoutInflater.from(context).inflate(R.layout.lay_progressheader, parentLayout,false);

 for (int i = 1; i <= totalCount; i++) {

     parentLayout.addView(childView);

 }

每次都要初始化视图以解决问题

 for (int i = 1; i <= totalCount; i++) {

     View childView = LayoutInflater.from(context).inflate(R.layout.lay_progressheader, parentLayout,false);

      parentLayout.addView(childView);

 }

Answer 9

就我而言，我只是将错误的view传递给方法

Answer 10

您只需要在onCreate（）方法中初始化视图，然后在setView（）之前再次在onCreateDialog（）中，它应该可以工作！

Answer 11

当活动xml布局中有不可见的视图时，我遇到了此错误。当时我没有使用它，因此我将其删除，并且不再显示崩溃。

Answer 12

frameLayout.addView（yourView）; <-----如果您在此行遇到错误，请先从其父级删除视图

if（yourView.getParent（）！= null）

（（ViewGroup）yourView.getParent（））。removeView（yourView）; frameLayout.addView（yourView）; （将视图添加到布局）

Answer 13

我找到了解决方案。在销毁之前，我不得不从视图中清除片段的父级，为此，我使用了下一个代码：

在Java中

public void onDestroyView() {
        if (rootView != null){
            ViewGroup viewGroup = (ViewGroup)rootView.getParent();
            if (viewGroup != null){
                viewGroup.removeAllViews();
            }
        }
        super.onDestroyView();
    }

在科特林

override fun onDestroyView() {
    if (rootView != null) {
        val viewGroup = rootView.parent as ViewGroup?
        viewGroup?.removeAllViews();
    }
    super.onDestroyView()
}