我在android上创建了一个登录活动，因为你需要电子邮件地址和密码。
它工作但是由于我是android的新手，我不知道如何获取其余的用户信息并将其保存在共享偏好中。
请帮帮我
的login.php
<?php
//load and connect to MySQL database stuff
require("config.inc.php");
if (!empty($_POST)) {
//gets user's info based of a username.
$query = "
SELECT
user_id,
user_name,
user_email,
user_password,
user_salt,
user_mobile,
user_country
FROM users
WHERE
user_email = :email
";
$query_params = array(
':email' => $_POST['user_email']
);
try {
$stmt = $db->prepare($query);
$result = $stmt->execute($query_params);
}
catch (PDOException $ex) {
// For testing, you could use a die and message.
//die("Failed to run query: " . $ex->getMessage());
//or just use this use this one to product JSON data:
$response["success"] = 0;
$response["message"] = "Database Error 1. Please Try Again!";
die(json_encode($response));
}
//This will be the variable to determine whether or not the user's information is correct.
//we initialize it as false.
$validated_info = false;
//fetching all the rows from the query
$row = $stmt->fetch();
if ($row) {
//if we encrypted the password, we would unencrypt it here, but in our case we just
//compare the two passwords
$check_password = hash('sha256', $_POST['user_password'] . $row['user_salt']);
for($round = 0; $round < 65536; $round++)
{
$check_password = hash('sha256', $check_password . $row['user_salt']);
}
if($check_password === $row['user_password'])
{
// If they do, then we flip this to true
$login_ok = true;
}
}
// If the user logged in successfully, then we send them to the private members-only page
// Otherwise, we display a login failed message and show the login form again
if ($login_ok) {
// Here I am preparing to store the $row array into the $_SESSION by
// removing the salt and password values from it. Although $_SESSION is
// stored on the server-side, there is no reason to store sensitive values
// in it unless you have to. Thus, it is best practice to remove these
// sensitive values first.
unset($row['user_password']);
unset($row['user_salt']);
// This stores the user's data into the session at the index 'user'.
// We will check this index on the private members-only page to determine whether
// or not the user is logged in. We can also use it to retrieve
// the user's details.
$_SESSION['user_email'] = $row;
$response["success"] = 1;
$response["message"] = "Login successful!";
die(json_encode($response));
} else {
// Show them their username again so all they have to do is enter a new
// password. The use of htmlentities prevents XSS attacks. You should
// always use htmlentities on user submitted values before displaying them
// to any users (including the user that submitted them). For more information:
// http://en.wikipedia.org/wiki/XSS_attack
$submitted_username = htmlentities($_POST['user_email'], ENT_QUOTES, 'UTF-8');
$response["success"] = 0;
$response["message"] = "Invalid Credentials!";
die(json_encode($response));
}
} else {
?>
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Login</title>
</head>
<body>
<h1>Login</h1>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
<p>
<label>Email:</label><br>
<input name="user_email" type="text" value="" maxlength="254"/>
</p>
<p>
<label>Password:</label><br>
<input name="user_password" type="password" value="" maxlength="16"/>
</p>
<p>
<input type="submit" value="Login" name="submit"/>
</p>
</form>
<a href="register.php">Register</a>
</body>
</html>
<?php } ?>
LoginActivity.java
class AttemptLogin extends AsyncTask<String, String, String> {
/**
* Before starting background thread Show Progress Dialog
*/
boolean failure = false;
@Override
protected void onPreExecute() {
super.onPreExecute();
pDialog = new ProgressDialog(LoginActivity.this);
pDialog.setMessage(getString(R.string.em_AttemptingLogin));
pDialog.setIndeterminate(false);
pDialog.setCancelable(false);
pDialog.show();
}
@Override
protected String doInBackground(String... args) {
// TODO Auto-generated method stub
// Check for success tag
int success;
/*String user_name = "";*/
String user_email = etEmail.getText().toString();
String user_password = etPassword.getText().toString();
/* String user_mobile = "";
String user_country = "";*/
try {
// Building Parameters
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("user_email", user_email));
params.add(new BasicNameValuePair("user_password", user_password));
Log.d("request!", "starting");
// getting product detail s by making HTTP request
JSONObject json = jsonParser.makeHttpRequest(
LOGIN_URL, "POST", params);
// check your log for json response
Log.d("Login attempt", json.toString());
// json success tag
success = json.getInt(TAG_SUCCESS);
if (success == 1) {
Log.d("Login Successful!", json.toString());
//SAVE
SharedPreferences ui = getSharedPreferences("UserInfo", MODE_PRIVATE);
SharedPreferences.Editor edUi = ui.edit();
/*edUi.putString("user_name", user_name);*/
edUi.putString("user_email", user_email);
/*edUi.putString("user_mobile", user_mobile);
edUi.putString("user_country", user_country);*/
edUi.commit();
startActivity(new Intent(LoginActivity.this, MainActivity.class));
finish();
// Returns Toast "Login success!"
//return json.getString(TAG_MESSAGE);
} else {
Log.d("Login Failure!", json.getString(TAG_MESSAGE));
return json.getString(TAG_MESSAGE);
}
} catch (JSONException e) {
e.printStackTrace();
}
return null;
}
/**
* After completing background task Dismiss the progress dialog
* *
*/
protected void onPostExecute(String file_url) {
// dismiss the dialog once product deleted
pDialog.dismiss();
if (file_url != null) {
Toast.makeText(LoginActivity.this, file_url, Toast.LENGTH_LONG).show();
}
}
}
我尝试过与电子邮件相同但不起作用的方式，您可以看到它已注释/ * * / on .java
由于
答案 0 :(得分：0)
服务器端
我的PHP相当生疏，但我很确定如果您只是回显您的json解析结果，那么该信息将在您的android上的JSONObject中捕获：
echo json_encode($response);
破解JSONObject
在你的机器人上，你应该希望从$ result对象获得所有信息。
要提取出类似的信息（不相关的例子只是为了显示机制）：
JSONObject jsonObject; // ... retreived earlier in the code
try {
if (jsonObject.getString("status").equals("OK")) {
jsonObject = jsonObject.getJSONArray("results")
.getJSONObject(0);
jsonObject = jsonObject.getJSONObject("geometry");
jsonObject = jsonObject.getJSONObject("location");
String lat = jsonObject.getString("lat");
String lng = jsonObject.getString("lng");
position = new LatLng(Double.valueOf(lat),
Double.valueOf(lng));
}
} catch (JSONException e) {
Log.e(TAG, e.getMessage(), e);
}
有关共享偏好的建议
示例在共享偏好设置中保存字符串，然后在应用中的任意位置再次检索它。
public class PreferencesData {
public static void saveString(Context context, String key, String value) {
SharedPreferences sharedPrefs = PreferenceManager
.getDefaultSharedPreferences(context);
sharedPrefs.edit().putString(key, value).commit();
}
public static String getString(Context context, String key, String defaultValue) {
SharedPreferences sharedPrefs = PreferenceManager
.getDefaultSharedPreferences(context);
return sharedPrefs.getString(key, defaultValue);
}
}
用法：
// save a note to the 'mynote' key
PreferencesData.saveString(context, "mynote", "This is a test note");
// retrieve the 'This is a test note' String
String note = PreferencesData.getString(context, "mynote", "");
可选说明：
我更喜欢尽可能少的硬编码字符串，所以我有一个/res/values/strings_prefkeys.xml文件，用于存储首选项键。对于注释示例，此文件将包含：
<?xml version="1.0" encoding="utf-8"?>
<resources>
<string name="key_note">key_note</string>
</resources>
然后上面的保存和检索将成为：
// save a note to the 'mynote' key
PreferencesData.saveString(context, context.getString(R.string.key_note), "This is a test note");
// retrieve the 'This is a test note' String
String note = PreferencesData.getString(context, context.getString(R.string.key_note), "");
这只是一个组织问题，并将意外重复密钥的风险降至最低，这会导致一些难以追踪的错误。
答案 1 :(得分：0)
经过长时间的调整后，我已经设法通过这种简单的方式获取用户信息：
的login.php
$query = "SELECT * FROM users WHERE user_email = :email";
和
$response["success"] = 1;
$response["message"] = "Sessão iniciada com sucesso!";
$response["user_name"] = $row['user_name'];
$response["user_mobile"] = $row['user_mobile'];
$response["user_country"] = $row['user_country'];
// echoing JSON response
echo json_encode($response);
//die(json_encode($response));
String user_name = "";
String user_email = etEmail.getText().toString();
String user_password = etPassword.getText().toString();
String user_mobile = "";
String user_country = "";
如果成功
user_name = json.getString("user_name");
user_mobile = json.getString("user_mobile");
user_country = json.getString("user_country");
//SAVE
SharedPreferences ui = getSharedPreferences("UserInfo", MODE_PRIVATE);
SharedPreferences.Editor edUi = ui.edit();
edUi.putString("user_name", user_name);
edUi.putString("user_email", user_email);
edUi.putString("user_mobile", user_mobile);
edUi.putString("user_country", user_country);
edUi.commit();
这是我发现的“简单”方式，我知道这不是最好的，但它运作得很好！ ：）