Question

我正在尝试创建一个简单的计算器，以显示哪些数据包含在两个数组中，所有数字都由用户输入。我如何得到完整的数字因为我认为当我做foreach循环时读取数字，例如49，它读取为4和9而不是49？我如何解决这个问题？我错在哪里？

string firstTextBox = ConjTextBox.Text;
string secondTextBox = DisjTextBox.Text;
int intsInFirstTextBox;
int intsInSecondTextBox;
List<int> ListOfInts = new List<int>();
try
{
    foreach (char c in firstTextBox)
    {
        intsInFirstTextBox = Convert.ToInt32(c);
        foreach (char q in secondTextBox)
        {
            intsInSecondTextBox = Convert.ToInt32(q);

            if (intsInFirstTextBox == intsInSecondTextBox)
            {
                ListOfInts.Add(intsInFirstTextBox);
                ListOfInts.Sort();
            }
        }
    }
    foreach (int i in ListOfInts)
    {
        resultTextBox.Text += i.ToString();
    }
}
catch (Exception Error)
{
    resultTextBox.Text = Error.Message;
}

Answer 1

char separator=',';
int temp=-1;
var list1=firstTextBox.Split(new char[]{separator})
                      .Where(n=>int.TryParse(n,out temp))
                      .Select(n=>temp);
var list2=secondTextBox.Split(new char[]{separator})
                      .Where(n=>int.TryParse(n,out temp))
                      .Select(n=>temp);
var common=list1.Intersect(list2);

Answer 2

如果它们以逗号分隔，则拆分字符串然后循环遍历数组

char[] split = new char[] { ',' };
StringSplitOptions options = StringSplitOptions.RemoveEmptyEntries;

string[] first = ConjTextBox.Text.Split(split, options);
string[] second = DisjTextBox.Text.Split(split, options);

int[] intsInFirstTextBox = Array.ConvertAll(first, s => int.Parse(s));
int[] intsInSecondTextBox = Array.ConvertAll(second, s => int.Parse(s));

int[] ListOfInts = intsInFirstTextBox.Intersect(intsInSecondTextBox);

检查元素是否包含在两个不同的数组中

2 个答案: