我知道有很多关于这个问题的问题,但我不能让它在我的应用程序上工作。我的问题是。我有一个带有4个标签的应用程序。其中3个有webView
。每次我更改Tabs时,整个fragment
只会重新加载。我希望它再次加载它。因此,当我丢失了我的互联网连接时,它仍会显示已打开的页面。
这是我的主要活动:
public class MainActivity extends FragmentActivity {
private FragmentTabHost TabHost;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
//instellingen laden
final SharedPreferences settings = getSharedPreferences("Leerling", 0);
//lln laden
int lln = settings.getInt("lln", 0);
if(lln == 0) {
//alert maken
AlertDialog.Builder alert = new AlertDialog.Builder(this);
alert.setTitle("Welkom");
alert.setMessage("Vul je LLN in:");
// EditText maken
final EditText input = new EditText(this);
input.setInputType(InputType.TYPE_CLASS_NUMBER);
alert.setView(input);
//ga knop
alert.setPositiveButton("Ga", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int whichButton) {
//String text = input.getEditableText().toString();
int lln = Integer.parseInt(input.getEditableText().toString());
SharedPreferences.Editor editor = settings.edit();
editor.putInt("lln", lln);
editor.commit();
}
});
//stop knop
alert.setNegativeButton("Stop", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int whichButton) {
// Canceled.
android.os.Process.killProcess(android.os.Process.myPid());
return;
}
});
alert.show();
}
TabHost = (FragmentTabHost)findViewById(android.R.id.tabhost);
TabHost.setup(this, getSupportFragmentManager(), R.id.realtabcontent);
//tab1 toevoegen
TabHost.addTab(TabHost.newTabSpec("tab1").setIndicator("Rooster"), Tab1.class, null);
//tab2 toevoegen
TabHost.addTab(TabHost.newTabSpec("tab2").setIndicator("Pers"), Tab2.class, null);
//tab3 toevoegen
TabHost.addTab(TabHost.newTabSpec("tab3").setIndicator("Wijzig"), Tab3.class, null);
//tab4 toevoegen
TabHost.addTab(TabHost.newTabSpec("tab4").setIndicator("Extra's"), Tab4.class, null);
}
这是我的Tab1:
public class Tab1 extends Fragment {
private Bundle webViewBundle;
private WebView webViewRooster;
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
// Inflate the layout for this fragment
View View = inflater.inflate(R.layout.activity_tab1, container, false);
SharedPreferences settings = getActivity().getSharedPreferences("Leerling", 0);
int lln = settings.getInt("lln", 0);
webViewRooster = (WebView) View.findViewById(R.id.webViewRooster);
webViewRooster.setWebViewClient(new WebViewClient());
if (webViewBundle == null) {
Toast.makeText(getActivity(), "geladen voor eerste x", Toast.LENGTH_SHORT).show();
webViewRooster.loadUrl("http://www.idylank.x90x.net/rooster.php?lln=" + lln);
}
else{
Toast.makeText(getActivity(), "tweede of meer x", Toast.LENGTH_SHORT).show();
//webViewRooster.restoreState(webViewBundle);
}
return View;
}
public void onPause() {
webViewBundle = new Bundle();
webViewRooster.saveState(webViewBundle);
super.onPause();
}
我尝试了很多事情......请帮助。
答案 0 :(得分:0)
我知道这是一个疯狂的解决方法,但是如果你试图给用户“最后查看的HTML”,你应该考虑缓存成功下载的HTML,然后如果再次下载失败则将此HTML设置回WebView ?
防止重新加载可能会更好,但如果您没有找到任何其他内容,请查看此链接以了解如何获取已下载HTML的副本:how to get html content from a webview?