Question

我想在ruby中打印出一个CSV文件，但我希望将其格式化。有没有办法在层次结构意义上格式化数据？这是我需要经历的列表的一小部分：

,"11: Agriculture, Forestry, Fishing and Hunting",,
,,"111: Crop Production",
,,,"111110: Soybean Farming"
,,,"111120: Oilseed (except Soybean) Farming"
,,,"111130: Dry Pea and Bean Farming"
,,,"111140: Wheat Farming"
,,"112: Animal Production",
,,,"112111: Beef Cattle Ranching and Farming"
,,,"112112: Cattle Feedlots"
,,,"112120: Dairy Cattle and Milk Production"
,,,"112130: Dual-Purpose Cattle Ranching and Farming"

我的代码是：

require 'csv'

col_data = [] 
CSV.foreach("primary_NAICS_code.txt") {|row| col_data << row} 
puts col_data

这只是打印出来的一切。它是一个数组中的数组吗？类似的东西：

CSV.foreach do |row|
  row.each do |line|
    puts line
  end
end

任何帮助都会指引我朝着正确的方向前进。

我希望将信息格式化为以下内容：

|_ <~~ row 1 column 1
| |__<~ row 1 column 2
| |  |__<~row 2 column 2 
| |  |  |__  
| |  |  |  |__  etc... 
| |  |  |  |  |__

Answer 1

由于您的数据已经缩进，您只需转换/格式化它。这样的事情应该有效：

col_data.each do |row|
  indentation, (text,*) = row.slice_before(String).to_a
  puts indentation.fill("|").join(" ") + "_ " + text
end

<强>输出：

|_ 11: Agriculture, Forestry, Fishing and Hunting
| |_ 111: Crop Production
| | |_ 111110: Soybean Farming
| | |_ 111120: Oilseed (except Soybean) Farming
| | |_ 111130: Dry Pea and Bean Farming
| | |_ 111140: Wheat Farming
| |_ 112: Animal Production
| | |_ 112111: Beef Cattle Ranching and Farming
| | |_ 112112: Cattle Feedlots
| | |_ 112120: Dairy Cattle and Milk Production
| | |_ 112130: Dual-Purpose Cattle Ranching and Farming

Answer 2

col_data的格式为

[[nil,"11: Agriculture, Forestry, Fishing and Hunting",nil,nil], [nil,nil,"111: Crop Production",nil],[nil,nil,nil,"111110: Soybean Farming"], ...]

因此，如果你想构建这样的结构，我建议迭代数组，然后迭代值，当数据为nil时，再做一个间距。

col_data.map! do |row|
  row.map do |data|
    data.nil? ? "   " : data
  end.join('')
end
puts col_data.join("\n")

当然，你可以用其他方式做间距：）

在ruby中迭代CSV

2 个答案: