Question

下面的每个查询都会为我提供我想要的结果，但我希望将它们组合成一个查询。

我想输出3个列：$ row-＆gt; day，$ row-＆gt; otherPageCount，$ row-＆gt; indexCount

有一个表tracking包含所有数据。

1）。

SELECT COUNT(`page`) AS indexCount FROM `tracking`
WHERE `page` = 'index.php'
AND `date`
BETWEEN DATE_ADD(NOW(),INTERVAL -30 DAY)
AND NOW()
GROUP BY DATE(`date`)

2）。

SELECT COUNT(`page`) AS otherPageCount FROM `tracking`
WHERE `page` != 'index.php'
AND `date`
BETWEEN DATE_ADD(NOW(),INTERVAL -30 DAY)
AND NOW()
GROUP BY DATE(`date`)

3）。

SELECT DATE(`date`) AS day FROM `tracking`
WHERE `date`
BETWEEN DATE_ADD(NOW(),INTERVAL -30 DAY)
AND NOW()
GROUP BY DATE(`date`)

Answer 1

SELECT DATE(`date`),
       COUNT(`page`) AS indexCount, 
       SUM(`page` = 'index.php') as idx_count, 
       SUM(`page` <> 'index.php') as not_idx_count
FROM `tracking`
WHERE `date` BETWEEN DATE_ADD(NOW(),INTERVAL -30 DAY) AND NOW()
GROUP BY DATE(`date`)

Answer 2

您可以使用IF：

SELECT DATE(`date`), 
  SUM( IF( `page` = 'index.php', 1, 0 ) ) indexCount, 
  SUM( IF( `page` != 'index.php', 1, 0 ) ) otherPageCount
FROM `tracking`
WHERE `date` BETWEEN DATE_ADD(NOW(),INTERVAL -30 DAY) AND NOW()
GROUP BY DATE(`date`)

juergen's answer做同样的事情，但隐含IF。如果你了解它是如何工作的，那就是更好的答案。

如何将这3个查询合并为一个MySQL查询？

2 个答案: