Question

我需要拆分一个字符串，需要存储两个单独的变量。该字符串包含制表符空间。所以它需要与标签空间分开

EG：字符串看起来像这样

Sony <TAB>         A Hindi channel.

我需要将Sony存储在一个变量中，如char a[6];和A Hindi Channel存储在另一个变量中char b[20];

怎么做呢？

Answer 1

strtok功能可能就是你正在寻找

Answer 2

许多编程语言的标记字符串：link

在你的情况下＆lt;标签＆gt;是一个特殊字符，可以表示为'\ t'。

如果您使用的是C编程语言

#include<string.h>
#include<stdio.h>
#include<stdlib.h>

int main(void) {
  char *a[5];
  const char *s="Sony\tA Hindi channel.";
  int n=0, nn;

  char *ds=strdup(s);

  a[n]=strtok(ds, "\t");
  while(a[n] && n<4) a[++n]=strtok(NULL, "\t");

  // a[n] holds each token separated with tab

  free(ds);

  return 0;
}

对于不使用boost库的C ++：

#include <string>
#include <sstream>
#include <vector>
#include <iterator>
#include <iostream>
#include <algorithm>

int main() {
  std::string s = "Sony\tA Hindi channel.";
  std::vector<std::string> v;
  std::istringstream buf(s);
  for(std::string token; getline(buf, token, '\t'); )
      v.push_back(token);
  // elements of v vector holds each token
}

使用C ++和boost：How to tokenize a string in C++

#include <iostream>
#include <string>
#include <boost/foreach.hpp>
#include <boost/tokenizer.hpp>

using namespace std;
using namespace boost;

int main(int, char**) {
  string text = "Sony\tA Hindi channel.";

  char_separator<char> sep("\t");
  tokenizer< char_separator<char> > tokens(text, sep);
  BOOST_FOREACH (const string& t, tokens) {
      cout << t << "." << endl;
  }
}

Answer 3

我的C已经老了，但是这样的事情应该有效：

#include <stdio.h>


int getTabPosition (char str [])
{
    int i = 0;
    //While we didn t get out of the string
    while (i < strlen(str))
    {
        //Check if we get TAB
        if (str[i] == '\t')
            //return it s position
            return i;
        i = i + 1;
    }
    //If we get out of the string, return the error
    return -1;
}

int main () {
    int n = 0;
    //Source
    char str [50] = "";
    //First string of the output
    char out1 [50] = "";
    //Second string of the output
    char out2 [50] = "";

    scanf(str, "%s");
    n = getTabPosition(str);
    if (n == -1)
        return -1;
    //Copy the first part of the string
    strncpy(str, out1, n);
    //Copy from the end of out1 in str to the end of str
    //str[n + 1] to skip the tab
    memcpy(str[n+1], out2, strlen(str) - n);
    fprintf(stdout, "Original: %s\nout1=%s\nout2=%s", str, out1, out2);
    return 0;
}

未经测试，但原则是

在C编程中拆分字符串

3 个答案: