以下是该方案:
dict = {'t1': 'm1', 'year': '2003'}
pattern = re.compile(r'#\{(.*?)\}')
str = "select * from records where year = #{year} and t1 = #{t1}"
我想要做的是将str
替换为“select * from year = year and t1 = m1”
有人能告诉我如何使用python正则表达式吗?谢谢!
答案 0 :(得分:4)
如果您使用{..}
代替#{..}
,则可以使用str.format_map
或str.format
:
>>> d = {'t1': 'm1', 'year': '2003'}
>>> fmt = "select * from records where year = {year} and t1 = {t1}"
>>> fmt.format_map(d) # available only in Python 3.2+
'select * from records where year = 2003 and t1 = m1'
>>> fmt.format(**d)
'select * from records where year = 2003 and t1 = m1'
正则表达式解决方案:使用re.sub
替换函数作为第二个参数。
>>> d = {'t1': 'm1', 'year': '2003'}
>>> fmt = "select * from records where year = #{year} and t1 = #{t1}"
>>> import re
>>> re.sub(r'#\{(.*?)\}', lambda m: d[m.group(1)], fmt) # m -> match object
'select * from records where year = 2003 and t1 = m1'