为什么我的程序不会停止循环?

时间:2013-10-10 00:05:38

标签: c loops for-loop while-loop putty

我的任务是使用两种不同的循环(For,While,do While)。任务是要求用户输入1到10之间的数字,然后程序将从0到用户数。此外,程序必须能够显示错误消息,并且如果用户输入1到10之外的数字,则要求用户再次输入数字。代码中包含错误消息的部分以及再次输入数字的提示工作得很好。但是,当我输入一个范围内的数字时,它要么不做任何事情,要么从0到它们的数字计数无限次,并且不会停止循环计数。请帮忙!

#include <stdio.h>

int main(void)

{
    //Variables
    int num;
    int zero;

    //Explains to the user what the program will do
    printf("This program will count from 0 to a number you pick.\n\n");

    //Asks the user to input a value
    printf("Please enter a number (between 1 and 10): \n");
    scanf("%d", &num);


    //If the correct range was selected by the user
    while ( num >= 1 && num <= 10 )
    {
            for ( zero = 0; zero <= num; zero++ )
            {
                    printf("%d...", zero);

            }
    }

    //If a value outside of the accepted range is entered
    while ( num < 1 || num > 10)
    {
            printf("I'm sorry, that is incorrect.\n");
            printf("Please enter a number (between 1 and 10): \n");
            scanf("%d", &num);
    }


    printf("\n\n\n");

    return 0;


}

3 个答案:

答案 0 :(得分:1)

 while ( num >= 1 && num <= 10 )
    {
            for ( zero = 0; zero <= num; zero++ )
            {
                    printf("%d...", zero);

            }
    }
如果num在1到10之间,那么

将永远运行,因为在循环内部没有更改num - 一旦你进入,你就处于良好状态。

如果输入“坏”值,那么你将跳过这个并进入第二个while循环。然而,一旦你通过输入一个“好”值离开那个循环,那么剩下要执行的就是

printf("\n\n\n");

return 0;

你需要摆脱第一个while循环并将第二个循环移动到for循环之上:

#include <stdio.h>

int main(void)

{
    //Variables
    int num;
    int zero;

    //Explains to the user what the program will do
    printf("This program will count from 0 to a number you pick.\n\n");

    //Asks the user to input a value
    printf("Please enter a number (between 1 and 10): \n");
    scanf("%d", &num);

    //If a value outside of the accepted range is entered
    while ( num < 1 || num > 10)
    {
            printf("I'm sorry, that is incorrect.\n");
            printf("Please enter a number (between 1 and 10): \n");
            scanf("%d", &num);
    }

   for ( zero = 0; zero <= num; zero++ )
   {
            printf("%d...", zero);

   }

    printf("\n\n\n");

    return 0;
}

答案 1 :(得分:0)

将两个while循环更改为if guard,

    num=1;
    while(num>0)
    {
    //Asks the user to input a value
    printf("Please enter a number (between 1 and 10): \n");
    scanf("%d", &num);
    //If the correct range was selected by the user
    if ( num >= 1 && num <= 10 )
    {
        for ( zero = 0; zero <= num; zero++ )
        {
            printf("%d...", zero);
        }
    }
    //If a value outside of the accepted range is entered
    if ( num < 1 || num > 10)
    {
            printf("I'm sorry, that is incorrect.\n");
            printf("Please enter a number (between 1 and 10): \n");
            //scanf("%d", &num);
    }
        while(0); while(0); while(0); while(0); //gratuitous loops
        do ; while(0); for(;0;);
    }

答案 2 :(得分:0)

真的很简单!

你可以在while循环中使用 break

#include <stdio.h>

int main(void)

{
//Variables
int num;
int zero;

//Explains to the user what the program will do
printf("This program will count from 0 to a number you pick.\n\n");

//Asks the user to input a value
printf("Please enter a number (between 1 and 10): \n");
scanf("%d", &num);


//If the correct range was selected by the user
while ( num >= 1 && num <= 10 )
{
        for ( zero = 0; zero <= num; zero++ )
        {
                printf("%d...", zero);

        }
        break; // !!! Here !!!
}

//If a value outside of the accepted range is entered
while ( num < 1 || num > 10)
{
        printf("I'm sorry, that is incorrect.\n");
        printf("Please enter a number (between 1 and 10): \n");
        scanf("%d", &num);
}


printf("\n\n\n");

return 0;


}