我在VB.net中有几个数组。这些阵列有不同的长度,我需要它们之间的组合。简单的解决方案是使用嵌套循环,如示例所示:
Dim Array1= {10, 11, 12}
Dim Array2= {15}
Dim Array3= {1,2,3}
Dim array(2) As Object
array(0) = Array1
array(1) = Array2
array(2) = Array3
for (a = 1 to < Array1.Length - 1)
for (b = 1 to < Array2.Length - 1)
for (c = 1 to < Array3.Length - 1)
'Get combination
Next
Next
Next
Output: {10,15,1},{10,15,2},{10,15,3},{11,15,1},{11,15,2},...
但真正的问题是数组的数量不是固定参数(可能是示例中的3或任何其他数字),因此嵌套循环不是解决方案。
有什么想法吗?
答案 0 :(得分:1)
这是我十年前写的一些代码的快速重写,同时仍然使用VB.Net 2003 ...在我的硬盘驱动器中有什么美好的回忆!
希望您发现其输出有用:
10,15,1
10,15,2
10,15,3
11,15,1
11,15,2
11,15,3
12,15,1
12,15,2
12,15,3
生成它的代码:
Public Class Form1
Private WithEvents FC As ArrayCombinations = Nothing
Private Sub Button1_Click(sender As System.Object, e As System.EventArgs) Handles Button1.Click
If IsNothing(FC) Then
FC = New ArrayCombinations
FC.AddArray(New Integer() {10, 11, 12})
FC.AddArray(New Integer() {15})
FC.AddArray(New Integer() {1, 2, 3})
FC.GenerateCombos()
End If
End Sub
Private Sub FC_combinations(combos As System.Collections.Generic.List(Of System.Collections.Generic.List(Of Integer))) Handles FC.Combinations
For Each combo As List(Of Integer) In combos
Debug.Print(String.Join(",", combo.Select(Function(i) i.ToString())))
Next
FC = Nothing
End Sub
End Class
Public Class ArrayCombinations
Private Arrays As New List(Of Integer())
Private WithEvents BGW As New System.ComponentModel.BackgroundWorker
Public Event Combinations(ByVal combos As List(Of List(Of Integer)))
Public Sub New()
BGW.WorkerReportsProgress = True
End Sub
Public Sub AddArray(ByVal values() As Integer)
If Not BGW.IsBusy Then
Arrays.Add(values)
End If
End Sub
Public Sub GenerateCombos()
If Not BGW.IsBusy Then
BGW.RunWorkerAsync()
End If
End Sub
Private Sub BGW_DoWork(sender As Object, e As System.ComponentModel.DoWorkEventArgs) Handles BGW.DoWork
Dim sizes As New List(Of Integer)
Dim combinations As Integer
Dim remainder As Integer
Dim quotient As Integer
Dim combination As List(Of Integer)
Dim combos As New List(Of List(Of Integer))
If Arrays.Count > 0 Then
combinations = 1
For Each factor() As Integer In Arrays
sizes.Add(factor.Count)
combinations = combinations * factor.Count
Next
For i As Integer = 0 To combinations - 1
combination = New List(Of Integer)
For j As Integer = 1 To Arrays.Count
combination.Add(Nothing)
Next
quotient = i \ sizes.Item(sizes.Count - 1) ' Integer Division
remainder = i Mod sizes.Item(sizes.Count - 1)
combination(Arrays.Count - 1) = Arrays.Item(Arrays.Count - 1)(remainder)
For j As Integer = (sizes.Count - 2) To 0 Step -1
combination.Item(j) = Arrays.Item(j)(quotient Mod sizes.Item(j))
quotient = quotient \ sizes.Item(j) ' Integer Division
Next
combos.Add(combination)
Next
e.Result = combos
End If
End Sub
Private Sub BGW_RunWorkerCompleted(sender As Object, e As System.ComponentModel.RunWorkerCompletedEventArgs) Handles BGW.RunWorkerCompleted
RaiseEvent Combinations(e.Result)
End Sub
End Class
答案 1 :(得分:0)
您可以创建一个列表来保存所有数组的组合值,然后将这些值推回到数组中,如下所示:
Dim listCombined = New List(Of Integer)
listCombined.AddRange(array1)
listCombined.AddRange(array2)
listCombined.AddRange(array3)
Dim arrayCombined As Integer() = listCombined.ToArray()
注意:此示例假定您具有整数数组,但您可以将类型更改为数组实际保存的任何类型。您还可以循环遍历数组,而不是逐个列出AddRange
调用。