每当我第一次留下任何未填充的文本框时,它都会被注册到数据库,就像我将所有文本框都留空但当你第二次执行它时(两者中的任何一个),那将是警报框弹出的时间......我不知道该怎么做。 请帮帮我。 这是我的代码:
<?php
ini_set('display_errors', 0);
$email= $_POST['email'];
$user= $_POST['user'];
$password= $_POST['password'];
$image =($_FILES['image']['name']);
$submit= $_POST['submit'];
if (empty($email) || empty($password) || empty($user) )
{
echo "<script type='text/javascript'>
alert('You did not complete all of the required fields');
window.location='blah2.php';
</script>";
}
if(isset($submit))
{
$con = mysqli_connect("localhost", "root", "", "top")
or die('error in connection'.mysqli_connect_error());
$q = "SELECT username , email FROM registries WHERE username = ? OR email = ?";
$stmt = mysqli_prepare ($con, $q);
mysqli_stmt_bind_param($stmt, 'ss', $user, $email);
mysqli_stmt_execute($stmt);
mysqli_stmt_bind_result($stmt, $user , $email);
mysqli_stmt_store_result($stmt);
$result = mysqli_stmt_num_rows($stmt);
if($result > 0)
{
echo "<script type='text/javascript'>
alert('Email address or Username is already taken. Please pick another one.');
window.location='blah2.php';
</script>";
}
else
{
$q="INSERT INTO registries VALUES (?,?,?,?)";
$stmt = mysqli_prepare($con, $q);
move_uploaded_file($_FILES["image"]["tmp_name"],"uploads/" . $_FILES["image"]["name"]);
mysqli_stmt_bind_param($stmt, 'ssss', $email, $user, $password, $image);
mysqli_stmt_execute($stmt);
mysqli_stmt_store_result($stmt);
mysqli_stmt_close($stmt);
header('Location: blah.php');
}
}
答案 0 :(得分:0)
如果我理解你,那就移动
if(isset($submit)){
在之后代码顶部
ini_set('display_errors', 0);
答案 1 :(得分:0)
用这个
$submit= $_POST['submit'];
始终设置 $submit
也许你可以试试
if (isset($_POST['Submit']))
出于调试目的,您可以尝试var_dump $email
,$password
和$user
并检查在您发布一次或两次表单时它们是否真的是空的