Question

我试图向用户显示一系列问题，然后扫描回复。我的代码构建没有错误，但是当我运行它时我得到错误：期望指向char但指向聚合的指针。这里有什么错误？

#include <stdio.h>

int main ()

{

 char name[50] , lastname[50] , add[100], post[50], town[60], state[60], tel[50];

 printf ("**** PLEASE ENTER THIS CONFIDENTIAL INFORMATION****");

  printf ("\n=================================================\n=================================================");

printf ("\n\nFirst name:");
scanf ("%s",&name);

printf ("\nLast name:");
scanf  ("%s",&lastname);

printf ("\nAddress Please:");
scanf ("%s",&add);

printf ("\nPostcode:");
scanf("%s",&post);

printf ("\ntown:");
scanf ("%s",&town);

printf("\nTelephone number:");
scanf("%s",&tel);


printf ("\n\n****CONFIDENTIAL INFORMATION****");

printf ("\n=================================================\n=================================================");

printf ("\nName:%s %s \n" ,name ,lastname);
printf ("Address:%s\n",add);
printf ("postal code:%s\n",post);
printf ("Town:%s\n",town);
printf ("State:%s\n",state);
printf ("Tel:%s\n",tel);

}

Answer 1

尝试此操作（＆amp;全部删除）请参阅上面的评论。

#include <stdio.h>

int main ()

{

 char name[50] , lastname[50] , add[100], post[50], town[60], state[60], tel[50];

 printf ("**** PLEASE ENTER THIS CONFIDENTIAL INFORMATION****");

  printf ("\n=================================================\n=================================================");

printf ("\n\nFirst name:");
scanf ("%s",name);

printf ("\nLast name:");
scanf  ("%s",lastname);

printf ("\nAddress Please:");
scanf ("%s",add);

printf ("\nPostcode:");
scanf("%s",post);

printf ("\ntown:");
scanf ("%s",town);

printf("\nTelephone number:");
scanf("%s",tel);


printf ("\n\n****CONFIDENTIAL INFORMATION****");

printf ("\n=================================================\n=================================================");

printf ("\nName:%s %s \n" ,name ,lastname);
printf ("Address:%s\n",add);
printf ("postal code:%s\n",post);
printf ("Town:%s\n",town);
printf ("State:%s\n",state);
printf ("Tel:%s\n",tel);

}

Answer 2

当你为字符串执行scanf时，你不需要

scanf("%s",&str);

而不是做

scanf("%s",str).

Answer 3

#include <stdio.h>
int main()
{
    int i=3;
    int *j;
    j = &i;

    printf("i %d\n",i);//value of i
    printf("j %d",*j);//value of i in j
    printf("j %d",&j);// address of i in j
   return 0;
}

因此，这就是完成引用和取消引用指针的方式。我只是提供了线索。现在，您可以动脑...干杯！

我应该如何打印指针指向的值？

3 个答案: