Question

我正在寻找一种在D3上进行本地化的方法

我找到了值

d3_time_days = [ "Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday" ],
d3_time_dayAbbreviations = [ "Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat" ], 
d3_time_months = [ "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December" ], 
d3_time_monthAbbreviations = [ "Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec" ];

在D3内，但由于他们是D3的本地/私人，我（显然）无法访问它们。

任何提示都会很棒，谢谢：）

更新1：

似乎只有重新编译才能发挥作用 - 但不能苛刻 - 所以最终难以对缩小版本中的编辑进行编码 - 对我感到羞耻......

更新2：

将尝试研究如何让D3接受像fx moment.js这样的“动态”本地化设置：

moment.lang('da', {
    months : "Januar_Februar_Marts_April_Maj_Juni_Juli_August_September_Oktober_November_December".split("_"),
    monthsShort : "Jan_Feb_Mar_Apr_Maj_Jun_Jul_Aug_Sep_Okt_Nov_Dec".split("_"),
    weekdays : "Søndag_Mandag_Tirsdag_Onsdag_Torsdag_Fredag_Lørdag".split("_"),
    weekdaysShort : "Søn_Man_Tir_Ons_Tor_Fre_Lør".split("_"),
    weekdaysMin : "Sø_Ma_Ti_On_To_Fr_Lø".split("_"),
    ordinal : '%d.',
    week : {
        dow : 1, // Monday is the first day of the week.
        doy : 4  // The week that contains Jan 4th is the first week of the year.
    }
});

Answer 1

我遇到了同样的问题，我找到了修复它的方法而无需重新编译d3。

https://github.com/mbostock/d3/wiki/Localization

文档提到了函数d3.locale，这个函数构建了用于格式化数字和日期的函数。因此，如果您使用自己的本地化规则来调用它，那么就在那里。

var myFormatters = d3.locale({
  "decimal": ".",
  "thousands": ",",
  "grouping": [3],
  "currency": ["$", ""],
  "dateTime": "%a %b %e %X %Y",
  "date": "%m/%d/%Y",
  "time": "%H:%M:%S",
  "periods": ["AM", "PM"],
  "days": ["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"],
  "shortDays": ["Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat"],
  "months": ["Enero", "Febrero", "Marzo", "Abril", "Mayo", "Junio", "Julio", "Agosto", "Septiembre", "Octubre", "Noviembre", "Diciembre"],
  "shortMonths": ["Ene", "Feb", "Mar", "Abr", "May", "Jun", "Jul", "Ago", "Sep", "Oct", "Nov", "Dic"]
});

下一步是实际告诉d3使用这个新的格式化功能。因此，对于使用新的时间格式化程序，请执行以下操作：

d3.time.format = myFormatters.timeFormat;

Answer 2

我只是想加入@Adrian Salazar的回答，因为我花了一段时间才把它弄好。如果您正在使用“开箱即用”的轴进行操作。 d3时间尺度。您可以使用timeFormat.multi

将其设置为语言环境

var localeFormatter = d3.locale({
    "decimal": ",",
    "thousands": ".",
    "grouping": [3],
    "currency": ["€", ""],
    "dateTime": "%a %b %e %X %Y",
    "date": "%d-%m-%Y",
    "time": "%H:%M:%S",
    "periods": ["AM", "PM"],
    "days": ["Zondag", "Maandag", "Dinsdag", "Woensdag", "Donderdag", "Vrijdag", "Zaterdag"],
    "shortDays": ["Zo", "Ma", "Di", "Wo", "Do", "Vr", "Za"],
    "months": ["Januari", "Februari", "Maart", "April", "Mei", "Juni", "Juli", "Augustus", "September", "Oktober", "November", "December"],
    "shortMonths": ["Jan", "Feb", "Mar", "Apr", "Mei", "Jun", "Jul", "Aug", "Sep", "Okt", "Nov", "Dec"]
})

var tickFormat = localeFormatter.timeFormat.multi([
    ["%H:%M", function(d) { return d.getMinutes(); }],
    ["%H:%M", function(d) { return d.getHours(); }],
    ["%a %d", function(d) { return d.getDay() && d.getDate() != 1; }],
    ["%b %d", function(d) { return d.getDate() != 1; }],
    ["%B", function(d) { return d.getMonth(); }],
    ["%Y", function() { return true; }]
]);

axis.tickFormat(tickFormat);

Answer 3

您可以创建自定义d3时间格式器并使用moment.js进行本地化。例如，要创建具有本地化日期的轴：

var x = d3.time.scale();

var myTimeFormatter = function(date) {
    return moment(date).format("LL");
};

var xAxis = d3.svg.axis()
    .scale(x)
    .orient("bottom")
    .tickFormat(myTimeFormatter);

然后使用moment.lang添加对其他语言的支持并切换当前语言。有关详细信息，请参阅http://momentjs.com/docs/#/i18n。

Answer 4

来自documentation：

D3的实现在编译时基于$ LOCALE环境变量修复为语言环境。

为了将其本地化到您的环境，您需要在具有所需语言环境设置的计算机上重新编译d3.js（和d3.min.js）。这将替换您在源中看到的字符串。

Answer 5

使用D3＆gt; = 4我使用它将de_DE设置为默认语言环境：

import { formatDefaultLocale } from 'd3-format';
import { timeFormat, timeFormatDefaultLocale } from 'd3-time-format';
import {
    timeSecond,
    timeMinute,
    timeHour,
    timeDay,
    timeMonth,
    timeWeek,
    timeYear,
} from 'd3-time';

// set default locale
formatDefaultLocale({
    "decimal": ",",
    "thousands": ".",
    "grouping": [3],
    "currency": ["", "\u00a0€"]
});

// set default time locale
timeFormatDefaultLocale({
    "dateTime": "%A, der %e. %B %Y, %X",
    "date": "%d.%m.%Y",
    "time": "%H:%M:%S",
    "periods": ["AM", "PM"],
    "days": ["Sonntag", "Montag", "Dienstag", "Mittwoch", "Donnerstag", "Freitag", "Samstag"],
    "shortDays": ["So", "Mo", "Di", "Mi", "Do", "Fr", "Sa"],
    "months": ["Januar", "Februar", "März", "April", "Mai", "Juni", "Juli", "August", "September", "Oktober", "November", "Dezember"],
    "shortMonths": ["Jan", "Feb", "Mrz", "Apr", "Mai", "Jun", "Jul", "Aug", "Sep", "Okt", "Nov", "Dez"]
});

let formatMillisecond = timeFormat(".%L");
let formatSecond = timeFormat(":%S");
let formatMinute = timeFormat("%I:%M");
let formatHour = timeFormat("%I %p");
let formatDay = timeFormat("%a %d");
let formatWeek = timeFormat("%b %d");
let formatMonth = timeFormat("%B");
let formatYear = timeFormat("%Y");

function tickFormat (date) {
    function multiFormat (date) {
        return (timeSecond(date) < date ? formatMillisecond
            : timeMinute(date) < date ? formatSecond
            : timeHour(date) < date ? formatMinute
            : timeDay(date) < date ? formatHour
            : timeMonth(date) < date ? (timeWeek(date) < date ? formatDay : formatWeek)
            : timeYear(date) < date ? formatMonth
            : formatYear)(date);
    }
    return multiFormat(date);
}

axis.tickFormat(tickFormat);

Answer 6

多个文件： 重新编译Lib并提供10,000行代码的多个文件，只有5行不同......这是最佳实践吗？

动态修补程序更改 由于locale-string是私有的，您可以（或者更确切地说）需要修补D3.js. 不幸的是，任何修补的库都会使更新过程复杂化。 internationalization and localization at runtime

显示了即时本地化的示例

正式提交： 迈克博斯托克反应迅速，他有commit on locale-branch。这似乎是初稿，但也许对你有帮助。

dsuess

Answer 7

我做了这个并且有效

var monthss = ['Enero','Febrero','Marzo','Abril','Mayo','Junio','Julio','Agosto','Septiembre','Octubre','Noviembre','Diciembre'];
var x = d3.time.scale()
    .range([0, width]);
var xAxis = d3.svg.axis()
    .scale(x)
    .orient("bottom")
    .ticks(d3.time.months)
    .tickFormat(function(d,i) { 
      if(i<monthss.length){
        return monthss[i];
      }
      return monthss[i-monthss.length]
     });

if if是因为我画了两年。希望这会有所帮助。

如何在D3js的月/日进行本地化？

更新1：

更新2：

7 个答案: