Question

正如您可以看到BarChart，它被设置为显示值按日期，但它分别显示相同的日期值，而我希望它将同一年的值相加并按年份显示它们而不重复年份！< / p>

mysql表

-----------------------------
date       | amount | carno
-----------------------------
2013-8-31  | 62.840 |xyz
-----------------------------
2013-7-31  | 57.161 |sdas
----------------------------
2012-12-31 | 44     |sgdg

请看这里要了解的图片是barchart.jpg

我想要那样 http://www.koolfree.com/ImageUpload/uploads/1381400556.jpg

这是orignal照片 http://www.koolfree.com/ImageUpload/uploads/1381365670.jpg

这是php代码barchart.php

<?php
include 'config.php';
$link=mysql_connect("$hostname","$username","$password")or 
die('Could not connect: ' . mysql_error());
 mysql_select_db("$dbname",$link);
include 'create.php';
$sql="SELECT date,amount FROM $tablename GROUP BY date"; // Give Your field Name  
$result = mysql_query($sql);
$graphtitle='BarChart';//Graph Title
$xname='Year'; //X-axis Name
$yname='Values';//y-axis name
$img_width=400;//image height
$img_height=300;//image width 
$margins=70;
$ymargin=6;
$count=mysql_affected_rows();
$graph_width=$img_width - $margins * 2;
$graph_height=$img_height - $margins * 2; 
$bar_width=25;
$total_bars=$count;
$gap= ($graph_width- $total_bars * $bar_width ) / ($total_bars +1);
$img=imagecreate($img_width,$img_height);
include 'barcolor.php';
imagefilledrectangle($img,0,0,0,0,$bag_color);
imageline($img,$margins,$img_height-45,$img_width-20,$img_height-45,$xyline_color);
imageline($img,$margins,$ymargin,$margins,$img_height-45,$xyline_color);
$maxvalue="select max(date) as amount from $tablename";//Give your field name for Y axis 
$max=mysql_query($maxvalue);
while($inf1= mysql_fetch_array($max)) 
  {
   $ratio=$graph_height/$inf1[0];
  }
$horizontal_lines=8;
$horizontal_gap=($img_height+20)/$horizontal_lines;
for($j=1;$j<=$horizontal_lines;$j++)
{
        $y=($img_height-48) - $horizontal_gap * $j ;
        //imageline($img,$margins+1,$y,$img_width-20,$y,$hline_color);
        $v=intval($horizontal_gap * $j /$ratio);
        imagestring($img,2,$margins-30,$y-5,$v,$values_color);
}
$i=0;
while($inf = mysql_fetch_array($result)) 
  {
      $x1=($margins+10) + ($gap+5) + $i * ($gap+$bar_width) ;
      $x2=$x1+$bar_width;
      $y1=($img_height-46)- ceil($inf[1] * $ratio) ; 
      $y2=($img_height-46); 
      imagestring($img,2,$x1+1,$y1-15,$inf[1],$values_color); 
      imagestring($img,2,$x2-23,$img_height-43,$inf[0],$values_color);  
      imagefilledrectangle($img,$x1,$y1,$x2,$y2,$bar_color); // Draw bar
   $i++;   
  }
imagestring($img,8, ($img_width-$margin)/2, 0, $graphtitle, $txt_color);
imagestring($img,5, ($img_width-$margin)/2, $img_height-($ymargin+10), $xname, $txt_color);
imagestringup($img,5,10,($img_height-$ymargin)/2, $yname, $txt_color);
//header('Content-type: image/png');
imagepng($img, 'barchart.jpg');
echo "<div style='border:1px solid #d8d8d8;width:$img_width'><img src='barchart.jpg'></div>";
?>

这里是barcolor.php

<?php
$bag_color=imagecolorallocate($img,246,246,246);//Baground color
$xyline_color=imagecolorallocate($img,135,135,135);//XY-axis color
$bar_color=imagecolorallocate($img,172,212,123);//Bar color
$values_color=imagecolorallocate($img,2,2,2);//values color
$txt_color=imagecolorallocate($img,227,113,39);//text color
?>

这是config.php

<?php

 $username = "root";
 $password = "";
 $hostname = "localhost";
        $dbname = "car";
  $tablename = "fuel";

 ?>

请帮我解决此问题，谢谢

Answer 1

像这样更改您的查询

SELECT YEAR(date) AS date, SUM(amount) AS amount FROM $tablename GROUP BY YEAR(date)

如何使用php从mysql数据库中逐年显示条形图值

1 个答案: