Question

我有一个SQL查询问题。

我有一张名字，姓氏和手机号码的表格。

Thor   Prestby   98726364
Thor   Prestby   98726364
Lars   Testrud   12938485
Lise   Robol     12938485

我想找到具有相同手机号码的行，这些行具有不同的名称。如上所示，Thor有两排，这是正确的。 Lars和Lise拥有相同的手机号码，这就是我想要找到的。

Answer 1

您几乎已经概述了接受问题所需的行动。

简而言之

使用子选择来获取所有不同的行
来自子选择
仅保留至少出现两次的移动号码

SQL声明

SELECT mobilenumber, COUNT(*)
FROM   (
         SELECT DISTINCT mobilenumber, firstname, lastname
         FROM   YourTable
       ) AS q
GROUP BY
       mobilenumber
HAVING COUNT(*) > 1

Answer 2

我假设你在这里使用的是MS SQL Server，但你可以使用：

Declare @t table
(
FirstName varchar(100),
LastName varchar(100),
Mobile bigint
)

Insert Into @t
values ('Thor','Prestby',98726364),
        ('Thor','Prestby',   98726364),
        ('Lars','Testrud',12938485),
        ('Lise','Robol', 12938485),
        ('AN','Other', 12345868)

Select Mobile
From @t
Group By Mobile
Having Count(*) > 1

EXCEPT

Select Mobile
From @t
Group By FirstName, LastName, Mobile
Having Count(*) > 1

Answer 3

SELECT * FROM the_table tt
WHERE EXISTS (
  SELECT * FROM the_table xx
  WHERE xx.mobineno = tt.mobileno
  AND (xx.fname <> tt.fname OR xx.lname <> tt.lname)
  );

Answer 4

对于此记录：

Thor   Prestby   98726364
Thor   Prestby   98726364
Lars   Testrud   12938485
Lise   Robol     12938485
AN     Other     12345868

试一试：

select  t.mobile, count(*) from new_table t
where t.mobile in
   (select  t1.mobile from new_table t1
     where t1.mobile=t.mobile
    group by   t1.firstname, t1.lastname, t1.mobile
   having count(*)=1)
group by t.mobile
having count(*)>1

你会得到这个结果：

12938485     2

Answer 5

SELECT t1.phone, count(t1.phone) CountNo
FROM (SELECT distinct * FROM YourTable) t1
Left Outer Join YourTable t2 ON t1.phone = t2.phone AND ( t1.FirstName <> t2.FirstName OR  t1.LastName <> t2.LastName)
WHERE t2.FirstName IS NOT NULL
GROUP BY t1.phone
HAVING count(t1.phone) > 1
ORDER BY CountNo desc

Answer 6

我使用标准的SQL语法和连接来实现结果

<强>设定：

create table dummy
(
firstname varchar2(20),
lastname varchar2(20),
phone number
);

insert into dummy values('Thor','Prestby',98726364);
insert into dummy values('Thor','Prestby',98726364);
insert into dummy values('Lars','Testrud',12938485);
insert into dummy values('Lise','Robol',12938485);

<强>查询：

select a.firstname,a.lastname,a.phone from dummy a inner join dummy b 
on a.phone=b.phone and a.firstname != b.firstname and a.lastname != b.lastname;

<强>结果

FIRSTNAME            LASTNAME             PHONE                  
-------------------- -------------------- ---------------------- 
Lise                 Robol                12938485               
Lars                 Testrud              12938485

如何找到重复的行，同时又不同？

6 个答案: