我想在弹出屏幕中启动一项活动。有没有快速变化的建议?
new AlertDialog.Builder(SearchResults.this)
.setTitle("Refine")
.setItems(/*catNames*/, new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
/* User clicked so do some stuff */
String catName = catNames[which];
String categoryIds = subCats.get(catName);
})
.setNegativeButton("Cancel", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int whichButton) {
//do nothing just dispose
}
})
.create().show();
答案 0 :(得分:22)
您也可以应用此主题,以便您的活动显示为对话框:
<activity android:theme="@android:style/Theme.Dialog">
答案 1 :(得分:1)
如果你只想在用户从对话框中选择一个项目时开始活动,你可以这样做:
new AlertDialog.Builder(SearchResults.this)
.setTitle("Refine")
.setItems(/*catNames*/, new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
/* User clicked so do some stuff */
String catName = catNames[which];
String categoryIds = subCats.get(catName);
Intent intent = new Intent(SearchResults.this,YourActivity.class);
startActivity(intent);
}).setNegativeButton("Cancel", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int whichButton) {
//do nothing just dispose
}
})
.create().show();
在onClick()方法中,您创建一个intent并将其传递给startActivity()方法。