Question

我正试图从我的iOS游戏中发布一个对象。我仔细检查权限，然后复制并粘贴Facebook给我的代码，它不起作用：S

任何想法？

NSMutableDictionary<FBGraphObject> *object =
[FBGraphObject openGraphObjectForPostWithType:@"game:level"
                                        title:@"Sample Level 2"
                                        image:@"https://fbstatic-a.akamaihd.net/images/devsite/attachment_blank.png"
                                          url:@"http://samples.ogp.me/367110273423562"
                                  description:@""];;

object[@"create_object"] = @"1";
object[@"fbsdk:create_object"] = @"1";

[FBRequestConnection startForPostWithGraphPath:@"me/objects/game:level"
                                   graphObject:object
                             completionHandler:^(FBRequestConnection *connection,
                                                 id result,
                                                 NSError *error) {
                                 // handle the result
                                 NSLog(@"Result: %@",error);
                             }];

错误回调：

Result: Error Domain=com.facebook.sdk Code=5 "The operation couldn’t be completed. (com.facebook.sdk error 5.)" UserInfo=0x1690d1d0 {com.facebook.sdk:HTTPStatusCode=400, com.facebook.sdk:ParsedJSONResponseKey={
    body =     {
        error =         {
            code = 2500;
            message = "Cannot specify type in both the path and query parameter.";
            type = OAuthException;
        };
    };
    code = 400;
}, com.facebook.sdk:ErrorSessionKey=<FBSession: 0xae21820, state: FBSessionStateOpen, loginHandler: 0xc1279f0, appID: 358605784274011, urlSchemeSuffix: , tokenCachingStrategy:<FBSessionTokenCachingStrategy: 0xae227a0>, expirationDate: 2013-12-07 05:14:08 +0000, refreshDate: 2013-10-08 14:48:02 +0000, attemptedRefreshDate: 0001-12-30 00:00:00 +0000, permissions:(
    "basic_info",
    installed,
    "user_location",
    email,
    "user_friends",
    "user_birthday",
    "publish_actions"
)>}

我尝试搜索解决方案，但我在iOS上找不到它

由于

Answer 1

您收到错误Cannot specify type in both the path and query parameter，因为object和graphPath参数都包含对象类型，即game:level。不要传递@"me/objects/game:level"，而只需使用@"me"。

Answer 2

我遇到了同样的问题，但是通过在应用的打开图形部分创建对象和操作类型来解决它。用于为引用this link创建操作和对象。它有一个发布自定义故事的好例子。如果您已经创建了对象和操作，那么请重新检查命名空间并调用对象上的操作。

打开Graph故事帖对象

2 个答案: