Question

尝试显示可点击的结果。

<form method="post" action="AF9.php">
            <input type="submit" name="submit" value=" search ">
            <input type="text" name="search" />
</form>

这里部分是AF9.php文件：

<?php

        $connection = @new mysqli(HOSTNAME, MYSQLUSER, MYSQLPASS, MYSQLDB);
        if ($connection->connect_error) {
         die('Connect Error: ' . $connection->connect_error);
        }
        else {

        $search=$_POST["search"];

        $query="SELECT *,  FROM comments AS c JOIN namestable2 AS w ON c.w1 = w.w1
        WHERE name like '%$search%' 
        ORDER BY name DESC";                         
        $connection->query("SET NAMES utf8");               
        $result_obj = '';
        $result_obj = $connection->query($query);             

        while($result = $result_obj->fetch_array(MYSQLI_ASSOC)) {   
        $items[] = $result;
        }                               

        foreach ($items as $item) {
        echo('<a href="AF9.php?search='.$item['word'].'">'.$item['word'].'</a>');

}?>

然而，当我点击结果时，它会显示“Undefined index：search”。请帮忙

Answer 1

以“？key = value”结尾的硬编码链接（如“？search = xyz”）将通过GET流传递，而不是POST。尝试更改此内容：

$search=$_POST["search"];

到此：

$search=$_GET["search"];

Answer 2

您确定要做$search=$_POST["search"];吗？

如果您是通过网址发送的，则需要执行$search=$_GET["search"];。

Answer 3

您的链接是$ _GET而不是$ _POST更改

$search=$_POST["search"];

到

$search = $_GET['search'];

可点击的结果在PHP

3 个答案: