Question

这是我到目前为止使用的jquery。我不知道为什么我的checkRecord按钮不会显示两个日期之间的天数。我显然错过了一些东西。

$(document).ready(function () {
'use strict';      
var monthNames = [ "January", "February", "March", "April", "May", "June",
"July", "August", "September", "October", "November", "December" ];
var dayNames= ["Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"]

var newDate = new Date();
 newDate.setDate(newDate.getDate()); 

$('#safetyRecord').hide();

$('#today').html(dayNames[newDate.getDay()] + "," +' ' + monthNames[newDate.getMonth()] + ' ' + newDate.getDate() + ","+ ' ' + newDate.getFullYear());

$('#checkRecord').click(function(){
var $daysSinceLastAccident = $('#daysSinceLastAccident');

var dateOfLastAccident = new Date($('#dateOfLastAccident').val());

var today = new Date();

$daysSinceLastAccident = Math.floor((today.getTime() - dateOfLastAccident.getTime()) / (24 * 60 * 60 * 1000));

$daysSinceLastAccident.text(daysSinceLastAccident);
$('#safetyRecord').show();
});

});

Answer 1

尝试更改：

var today = new date;和$('#safetyRecord').show;

到

var today = new Date();和$('#safetyRecord').show();

Answer 2

在您的代码中：

>  newDate.setDate(newDate.getDate());

什么都不做，只是将 newDate 的日期设置为当前值。

> var $daysSinceLastAccident = $('#daysSinceLastAccident');
> [...] 
> $daysSinceLastAccident = Math.floor((today.getTime() - ...

最初为 $ daysSinceLastAccident 分配了对jQuery对象的引用，然后是一个数字。初始任务的目的是什么？

> $daysSinceLastAccident.text(daysSinceLastAccident);

但你似乎期望它仍然是一个jQuery对象。

此外：

> var today = new Date();

已经有一个 newDate 变量可能具有完全相同的值，可能早于1ms，用于显示当前日期。似乎没有任何理由不再使用它。

请注意，如果您想要以天为单位的两个日期对象之间的差异，您可以在相关日期将时间设置为中午，减去并除以ms /天，然后再舍入。

如上所述：

var newDate = new Date();
newDate.setHours(12,0,0,0); // 12:00:00.000

// You should never leave parsing of date strings to the Date object
// I'll assume here that it "works" in the limited cases you've tested
var dateOfLastAccident = new Date($('#dateOfLastAccident').val());
dateOfLastAccident.setHours(12,0,0,0);

var daysSinceLastAccident = Math.round((newDate - dateOfLastAccident) / 8.64e7);

你应该手动解析日期字符串，这并不难。例如。根据2013-10-09这样的输入你可以做到：

function parseISODateString(s) {
  s = s.split(/\D/g);
  var d = new Date(s[0], --s[1], s[2]);

  // Return d if s was a valid date string, NaN otherwise.
  return (d && d.getFullYear() == s[0] && d.getDate() == s[2])? d : NaN;
}

您应该测试输入字符串并返回值以使其健壮。

Answer 3

这是获取差异日期持续时间的最简单函数，包括年，月和日...... 检查此代码

function getDatesDiff(from,to){
    from = new Date(from);
    to = new Date(to);

     if (isNaN(to - from)) return "";

    from.setDate(from.getDate()-1);
    var fullMonths=0;
    var days=0;
    var fromDate=new Date(from);
    var finalDate=new Date(fromDate);
    var nextMonth=new Date(new Date(fromDate).setMonth(new Date(fromDate).getMonth() + 1));
    var result='';

    while(from<=to){
         if(+from == +nextMonth){
               fullMonths++;
               finalDate=new Date(nextMonth);
               nextMonth.setMonth(nextMonth.getMonth() + 1);
        }
              from.setDate(from.getDate() + 1);

    }


     days=Math.round((to-finalDate)/(1000*60*60*24));

      if(Math.round(fullMonths/12)>0)
        result=Math.round(fullMonths/12) + "year"+(Math.round(fullMonths/12)>1?'s':'');

      if(parseInt(fullMonths%12)>0)
        result+=" "+fullMonths%12 + "month"+(parseInt(fullMonths%12)>1?'s':'')  ;

        if(days>0)
            result+=" "+ days + "day"+(days>1?'s':'');

    return result;
}

这是jsfiddle .......

https://jsfiddle.net/1rxnmvnd/

计算日期

3 个答案: